I appreciate any help with the following questions: (1) Compute the check charac

Question

I appreciate any help with the following questions:

(1) Compute the check character for the following Code 39 message: *BIG FOOT*.

(2) Determine the single-precision checksum for the following five-character ASCII message:HOUSE.

(3) Determine the LRC and VRC for the following message (use even parity for LRC and odd parity for VRC): ASCIIspCODE

(4) Determine the BCC for the following data- and CRC-generating polynomials: G(x) = x7 + x4 + x2 + x0 = 10010101 P(x) = x5 + x4 + x1 + x0 = 110011

(5) Determine the Hamming bits for the ASCII character C (use odd parity and two stop bits). Insert the Hamming bits into every other location starting at the right.

Explanation / Answer

1Ans) The check values for all the characters except the start/stop character(*) are added together

message: *BIG FOOT*.

B          I           G         space   F        O         O         T

11    +   18   +     16   +    38    +   15   + 24   +   24   + 29   = 175

Dividing the sum by the constant 43 yields

                        175/43 = 4 with reminder of 3

There for final message is

*B I G space F O O T 3*.

Where 3 is the character with a check value of 3

4Ans)Determine the BCC for the following data- and CRC-generating polynomials:

G(x) = x7 + x4 + x2 + x0 = 10010101

P(x) = x5 + x4 + x1 + x0 = 110011

First G(x) is multiplied by the number of bits in the CRC code, which is 5

x5(x7 + x4 + x2 + x0) =x12 + x9 + x7 + x5 =1 0 0 1 0 1 0 1 0 0 0 0 0

                   ________ 1 1 1 0 1 0 1 0 0 0

1 1 0 0 1 1 ) 1 0 0 1 0 1 0 1 0 0 0 0 0 0

                    1 1 0 0 1 1

                       1 0 1 1 0 0

1 1 0 0 1 1

1 1 1 1 1 1

  1 1 0 0 1 1

1 1 0 0 0 0

1 1 0 0 1 1

1 1 0 0 0----->CRC

CRC appending to the data stream

G(x) + CRC = 1 0 0 1 0 1 0 1 1 1 0 0 0

5.Ans) Determine the Hamming bits for the ASCII character C (use odd parity and two stop bits). Insert the Hamming bits into every other location starting at the right.

ASCII code for C: 1 0 0 0 0 1 1

P S E

where P is parity bit

S is starting bit

E is Ending bit
  
starting bit : 0
ending bits : 11
parity bit :1

ASCII code for C: 1 0 0 0 0 1 1

Hamming bits = 0010 in positions 8, 6, 4, and 1

message with hamming code: 1 0 0 0 0 0 1 1 1 1
trasmitted signal: 11 1 100 0011 0 = 1 1 1 1 0 0 0 0 1 1 0

11 10 09 08 07 06 05 04 03 02 01 number the columns and highlight the powers of 2 1 0 0 ? 0 0 1 ? 1 ? ? insert your data in columns that aren't parity bits 1 0 0 1 1 ? taking the 1st power of 2^0 (1) check 1 skip 1 then work out the digit that is needed to go into column one to apply odd parity ? = 1 1 0 0 0 1 ? taking the 2nd power of 2^1 (2) check 2 skip 2 then work out the digit that is needed to go into column one to apply odd parity ? = 1 0 0 1 ? taking the 3rd power of 2^2 (4) check 4 skip 4, then work out the digit that is needed to go into column one to apply odd parity ? = 1 1 0 0 ? taking the 4th power of 2^3 (8) check 8 skip 8, then work out the digit that is needed to go into column one to apply odd parity ? = 0

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