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public class Homework1 { /** * minValue returns the minimum value in an array of

ID: 3780938 • Letter: P

Question

public class Homework1 {

   /**

   * minValue returns the minimum value in an array of doubles. You can assume

   * the array is nonempty and has no duplicates. Your solution must go

   * through the array exactly once. Your solution must not call any other

   * functions. Here are some examples (using "==" informally):

   *

   * <pre>

   * -7 == minValue (new double[] { 1, -4, -7, 7, 8, 11 })

   * </pre>

   */

   public static double minValue (double[] list) {

       return 0; //TODO: fix this with your code

   }

   /**

   * minPosition returns the position of the minimum value in an array of

   * doubles. The first position in an array is 0 and the last is the

   * array.length-1.

   *

   * You can assume the array is nonempty and has no duplicates. Your solution

   * must go through the array exactly once. Your solution must not call any

   * other functions. Here are some examples (using "==" informally):

   *

   * <pre>

   * 0 == minPosition(new double[] { -13, -4, -7, 7, 8, 11 })

   * </pre>

   */

   public static int minPosition (double[] list) {

       return 0; //TODO: fix this with your code

   }

   /**

   * distanceBetweenMinAndMax returns difference between the minPosition and

   * the maxPosition in an array of doubles.

   *

   * You can assume the array is nonempty and has no duplicates. Your solution

   * must go through the array exactly once. Your solution must not call any

   * other functions. Here are some examples (using "==" informally):

   *

   * <pre>

   * 1 == distanceBetweenMinAndMax(new double[] { 1, -4, -7, 7, 8, 11, -9 }) // -9,11

   * </pre>

   */

   public static int distanceBetweenMinAndMax (double[] list) {

       return 0; //TODO: fix this with your code

   }

   /**

   * The following tests below should pass if your methods above are correct.

   * It is required for you to write 5 more tests for each method to ensure your

   * methods above are written correctly.

   */

   public static void main(String[] args) {

      

       // minValue Test sample

       double minValue = minValue (new double[] { 1, -4, -7, 7, 8, 11 });

       if (minValue == -7) {

           System.out.println("The minValue test was successful.");

       } else {

           System.out.println("The minValue test was not successful.");

       }

      

       // minPosition Test sample

       double minPosition = minPosition(new double[] { -13, -4, -7, 7, 8, 11 });

       if (minPosition == 0) {

           System.out.println("The minPosition test was successful.");

       } else {

           System.out.println("The minPosition test was not successful.");

       }

       // distanceBetweenMinAndMax Test sample

       double distance = distanceBetweenMinAndMax(new double[] { 1, -4, -7, 7, 8, 11, -9 });

       if (distance == 1) {

           System.out.println("The distanceBetweenMinAndMax test was successful.");

       } else {

           System.out.println("The distanceBetweenMinAndMax test was not successful.");

       }

   }

}

Explanation / Answer

package snippet;

public class Homework1 {
     
/**
* minValue returns the minimum value in an array of doubles. You can assume
* the array is nonempty and has no duplicates. Your solution must go
* through the array exactly once. Your solution must not call any other
* functions. Here are some examples (using "==" informally):
*
* <pre>
* -7 == minValue (new double[] { 1, -4, -7, 7, 8, 11 })
* </pre>
*/
public static double minValue (double[] list) {
   double min=9999; //set minimum value
  
   for(int i=0;i<list.length;i++)
   {
       if(list[i]<min) //if current element is less than minimum
           min=list[i];
   }
return min; //return minimum value
}

/**
* minPosition returns the position of the minimum value in an array of
* doubles. The first position in an array is 0 and the last is the
* array.length-1.
*
* You can assume the array is nonempty and has no duplicates. Your solution
* must go through the array exactly once. Your solution must not call any
* other functions. Here are some examples (using "==" informally):
*
* <pre>
* 0 == minPosition(new double[] { -13, -4, -7, 7, 8, 11 })
* </pre>
*/
public static int minPosition (double[] list) {
   double min=9999;//set minimum value
   int pos=0;//set minimum value index
  
   for(int i=0;i<list.length;i++)
   {
       if(list[i]<min)//if current element is less than minimum
       {
           min=list[i]; //set minimum value
           pos=i;//set index
       }
   }
return pos;
}

/**
* distanceBetweenMinAndMax returns difference between the minPosition and
* the maxPosition in an array of doubles.
*
* You can assume the array is nonempty and has no duplicates. Your solution
* must go through the array exactly once. Your solution must not call any
* other functions. Here are some examples (using "==" informally):
*
* <pre>
* 1 == distanceBetweenMinAndMax(new double[] { 1, -4, -7, 7, 8, 11, -9 }) // -9,11
* </pre>
*/
public static int distanceBetweenMinAndMax (double[] list)
{
  
   double min=9999;//set minimum value
   int pos=0;//set minimum value index
  
   for(int i=0;i<list.length;i++)
   {
       if(list[i]<min)//if current element is less than minimum
       {
           min=list[i];//set minimum value
           pos=i;//set index
       }
   }
  
  
   double max=-9999;//set max value
   int pos1=0;//set index
  
   for(int i=0;i<list.length;i++)
   {
       if(list[i]>max)//check if current is greater
       {
           max=list[i];
           pos1=i;
       }
   }
  
   return Math.abs(pos1-pos);//return difference of two positions
}

/**
* The following tests below should pass if your methods above are correct.
* It is required for you to write 5 more tests for each method to ensure your
* methods above are written correctly.
*/
public static void main(String[] args) {
  
// minValue Test sample
double minValue = minValue (new double[] { 1, -4, -7, 7, 8, 11 });
if (minValue == -7) {
System.out.println("The minValue test was successful.");
} else {
System.out.println("The minValue test was not successful.");
}
  
// minPosition Test sample
double minPosition = minPosition(new double[] { -13, -4, -7, 7, 8, 11 });
if (minPosition == 0) {
System.out.println("The minPosition test was successful.");
} else {
System.out.println("The minPosition test was not successful.");
}

// distanceBetweenMinAndMax Test sample
double distance = distanceBetweenMinAndMax(new double[] { 1, -4, -7, 7, 8, 11, -9 });
if (distance == 1) {
System.out.println("The distanceBetweenMinAndMax test was successful.");
} else {
System.out.println("The distanceBetweenMinAndMax test was not successful.");
}

}

}

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Output:

The minValue test was successful.
The minPosition test was successful.
The distanceBetweenMinAndMax test was successful.