Biochemistry-enzyme kinetics help... The Concentration of Enzyme in all experime
ID: 37797 • Letter: B
Question
Biochemistry-enzyme kinetics help...
The Concentration of Enzyme in all experiments is 2.0uM
Calculate values of Km and Vmax for human adolase.
Calculate Km and Vmax for Giardia aldolase.
How long does a single catalytic event take for each enzyme?
What will be the Vo human aldolase at 8uM [Fructose]?
What will be the Vo Giardia aldolase at 8uM [Fructose]?
At what substrate concentration will the Vo equal 1.7 uM/s for human aldolase?
At what human aldolase concentration will vmax equal 7.0uM/s?
Human Aldolase Fructose um [S] Vo 1 0.576 3 1.075 6 1.373 Giardia Adolase Fructose um [S] Vo 1 2.63 3 4.532 6 5.532Explanation / Answer
For an enzyme-catalysed reaction, there is usually a hyperbolic relationship between the rate of reaction and the concentration of substrate.At low concentration of substrate, there is a steep increase in the rate of reaction with increasing substrate concentration. The catalytic site of the enzyme is empty, waiting for substrate to bind, for much of the time, and the rate at which product can be formed is limited by the concentration of substrate which is available.As the concentration of substrate increases, the enzyme becomes saturated with substrate. As soon as the catalytic site is empty, more substrate is available to bind and undergo reaction. The rate of formation of product now depends on the activity of the enzyme itself, and adding more substrate will not affect the rate of the reaction to any significant effect. The rate of reaction when the enzyme is saturated with substrate is the maximum rate of reaction, Vmax.
The relationship between rate of reaction and concentration of substrate depends on the affinity of the enzyme for its substrate. This is usually expressed as the Km (Michaelis constant) of the enzyme, an inverse measure of affinity.Km is the concentration of substrate which permits the enzyme to achieve half Vmax. An enzyme with a high Km has a low affinity for its substrate, and requires a greater concentration of substrate to achieve Vmax.".
vo =Vmax[S]/(KM+ [S]
vo/Vmax = [S]/(KM+ [S]).
1/ vo should be caluculated , later a upon double reciprocal plot is obtained , will get km and v amx values as Vmax = 0.665 ?M min-1 and Km = 0.24 mM .
a linear plot should be made for the giardia aldose.
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