Question 1: Assuming 4 stations with chip sequences defined as: A = (-1 -1 -1 +1
ID: 3777271 • Letter: Q
Question
Question 1:Assuming 4 stations with chip sequences defined as:
A = (-1 -1 -1 +1 +1 -1 +1 +1)
B = (-1 -1 +1 -1 +1 +1 +1 -1)
C = (-1 +1 -1 +1 +1 +1 -1 -1)
D = (+1 +1 +1 -1 -1 +1 -1 -1)
1) A CDMA receiver gets the following chip sequence: (1 +1 3 +1 1 3 +1 +1).
Which stations transmitted, and which bits did each one send? Show your calculations.
2) Suppose that A, B, and D are simultaneously transmitting 0 bits, using a CDMA system. What is the resulting chip sequence? Show your calculations. Question 1:
Assuming 4 stations with chip sequences defined as:
A = (-1 -1 -1 +1 +1 -1 +1 +1)
B = (-1 -1 +1 -1 +1 +1 +1 -1)
C = (-1 +1 -1 +1 +1 +1 -1 -1)
D = (+1 +1 +1 -1 -1 +1 -1 -1)
1) A CDMA receiver gets the following chip sequence: (1 +1 3 +1 1 3 +1 +1).
Which stations transmitted, and which bits did each one send? Show your calculations.
2) Suppose that A, B, and D are simultaneously transmitting 0 bits, using a CDMA system. What is the resulting chip sequence? Show your calculations. Question 1:
Assuming 4 stations with chip sequences defined as:
A = (-1 -1 -1 +1 +1 -1 +1 +1)
B = (-1 -1 +1 -1 +1 +1 +1 -1)
C = (-1 +1 -1 +1 +1 +1 -1 -1)
D = (+1 +1 +1 -1 -1 +1 -1 -1)
1) A CDMA receiver gets the following chip sequence: (1 +1 3 +1 1 3 +1 +1).
Which stations transmitted, and which bits did each one send? Show your calculations.
2) Suppose that A, B, and D are simultaneously transmitting 0 bits, using a CDMA system. What is the resulting chip sequence? Show your calculations.
Explanation / Answer
1. ANS
S · A = (+1 -1 +3 +1 -1 +3 +1 +1)/8 = 1
S · B = (+1 -1 -3 -1 -1 -3 +1 -1)/8 = -1
S · C = (+1 +1 +3 +1 -1 -3 -1 -1)/8 = 0
S · D = (+1 +1 +3 -1 +1 +3 +1 -1)/8 = 1
So station A transmits 1,
Station B transmits -1,
Station C transmits zero and
Station D Transmits 1.
2. ANS
A = (-1 -1 -1 +1 +1 -1 +1 +1)
A¯= (+1 +1 +1 -1 -1 +1 -1 -1)
B = (-1 -1 +1 -1 +1 +1 +1 -1)
B¯= (+1 +1 -1 +1 -1 -1 -1 +1)
D = (+1 +1 +1 -1 -1 +1 -1 -1)
D¯= (-1 -1 -1 +1 +1 -1 +1 +1)
A¯+B¯+D¯ = (+1 +1 -1 +1 -1 -1 -1 +1)
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