int i = 1, j = 1; for (i = 1; i < 4; i++) { for (j = 1; j < 4; j++) { Console.Wr

Question

            int i = 1, j = 1;
            for (i = 1; i < 4; i++)
            {
                for (j = 1; j < 4; j++)
                {
                    Console.Write("{0}{1} ", i, j);
                }
            }

       three
       four
       nine
       16

            int i = 1, j = 1;
            for (i = 1; i < 4; i++)
            {
                for (j = 1; j < 4; j++)
                {
                    Console.Write("{0}{1} ", i, j);
                }
            }

Explanation / Answer

for(i = 1; i < 4; i++);

Considering this, the loop starts with i value of 1, and will proceed as long as i value is less than 4, which is gradually increased by 1.

Therefore the loop runs for values, 1, 2, and 3. When the i value becomes 4, the condition (i < 4) fails, and therefore, the outer loop exits.

Hence the answer for your question is: three.

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