Write a program IN C, that counts the number of negative values, the number of p

Question

Write a program IN C, that counts the number of negative values, the number of positive values and the number of zeros in a floating point array. Instead of performing these counts inside the main program, each count should be calculated by a USER-DEFINED FUNCTION.

Specificially, the program should:

• greet the user,

• prompt for and input the length of the array;

• idiotproof the array length;

• dynamically allocate the array;

• check that the allocation was successful;

• prompt for and input the values in the array

• count the number of negative values by calling a USER-DEFINED FUNCTION;

• count the number of positive values by calling a USER-DEFINED FUNCTION;

• count the number of zeros by calling a USER-DEFINED FUNCTION;

• output the numbers of negative, positive and zero values in the array;

• deallocate the array.

NOTE: You MUST calculate each of the three counts in ITS OWN user-defined function; you are ABSOLUTELY FORBIDDEN to calculate more than one of them in the same user-defined function.

Explanation / Answer

int main()

{

float p_nArr[20]={0};

float nCount_Pos = 0;

float nCount_Neg = 0;

float num=0;

float SIZEOFARRAY= 0;

float index;

printf("nEnter the Size of the array");

scanf("%d",&SIZEOFARRAY);

printf("nEnter the elements ::n");

for( index = 0; index < SIZEOFARRAY; index++ )

{

scanf("%d",&p_nArr[index]);

if (p_nArr[index] > 0 )

nCount_Pos++ ;

else if (p_nArr[index] < 0 )

nCount_Neg++;

}

if ( nCount_Neg > 0)

{

printf("nNumber of negative numbers in the array are :: %dn", nCount_Neg);

for( index = 0; index < SIZEOFARRAY; index++ )

{

if (p_nArr[index] < 0 )

printf("%d ",p_nArr[index]);

}

}

if ( nCount_Pos > 0 )

{

printf("nNumber of Positive numbers in the array are :: %dn",nCount_Pos);

for( index = 0; index < SIZEOFARRAY; index++ )

{

if (p_nArr[index] > 0 )

printf("%d ",p_nArr[index]);

}

}

getch();

}

}

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