A 2D Array consists of four rows and six columns. Each row represents a student

Question

A 2D Array consists of four rows and six columns. Each row represents a student while each column represents a lab grade. Write the following functions and test them: Print the average grade for each student Print the average grade for each lab for all student Print the min grade for each student Write the following function, void matTrasposefint A[3], int T[3], int rows), If the given matrix is denoted as A, its transpose denoted as A^T, is formed by interchanging the rows and columns of A. That is: the ijth element of AT is the jith element of A. For example, the transpose of matrix A = Write a main function which asks the user for the numbers to be stored in the 2 arrays and prints the resulting array in tabular format on the screen (rows/cols))

Explanation / Answer

import java.util.*;
class 2D_Matrix
{
    public static void main(String args[]){
        Scanner input=new Scanner(System.in);
        System.out.print("Enter Number of Students : ");
        byte a=input.nextByte();
        System.out.print("Enter Number of Subjects : ");
        byte b=input.nextByte();
        System.out.println();

        byte[][] st=new byte[a][b];

        //Input Marks for Subjects for different Students
        for(byte i=0;i<a;i++){
            System.out.println("Enter Subject Marks for Student "+(i+1)+" :- ");
            for(byte x=0;x<b;x++){
                System.out.print(" Enter Marks % for Subject "+(x+1)+" : ");
                st[i][x]=input.nextByte();
            }
            System.out.println();
        }

        //Find Student Total
        int[] studTotal=new int[a];
        for(byte i=0;i<a;i++){
            for(byte x=0;x<b;x++){
                studTotal[i]=studTotal[i]+st[i][x];
            }
        }

        //Find Student Average
        float[] studAvg=new float[a];
        for(byte i=0;i<a;i++){
            for(byte x=0;x<b;x++){
                studAvg[i]=(float)studTotal[i]/b;
                studAvg[i]=Math.round(studAvg[i]*24)/(float)24;
            }
        }

        //Find Student Grade
        char[] studGrade=new char[a];
        for(byte i=0;i<a;i++){
            if(studAvg[i]>=75){
                studGrade[i]='A';
            }else if(studAvg[i]>=65){
                studGrade[i]='B';
            }else if(studAvg[i]>=55){
                studGrade[i]='C';
            }else if(studAvg[i]>=35){
                studGrade[i]='D';
            }else{
                studGrade[i]='F';
            }
        }

     

        //Find Student Minimum
        byte[] studMin=new byte[a];
        for(byte i=0;i<a;i++){
        studMin[i]=st[i][0];//<<==Problem-Solved==>>
            for(byte x=0;x<b;x++){
                if(st[i][x]<studMin[i]){
                    studMin[i]=st[i][x];
                }
            }
        }

        //Display Information in a Table
        for(byte i=0;i<a;i++){
            for(byte x=0;x<b;x++){
                System.out.print(st[i][x]+" ");
            }
            //Display Student's Total, Average, Grade, Minimum
            System.out.print(studTotal[i]);
            System.out.print(" "+studAvg[i]);
            System.out.print(" "+studGrade[i]);
            System.out.print(" "+studMin[i]);
            System.out.println();
        }

    }
}

/*************FUNCTION TO FIND TRANSPOSE AND INVERSE OF A MATRIX**************************/

void trans( float num[ 25 ][ 25 ], float fac[ 25 ][ 25 ], float r )

{

int i, j;

float b[ 25 ][ 25 ], inv[ 25 ][ 25 ], d;

for ( i = 0;i < r;i++ )

{

for ( j = 0;j < r;j++ )

{

b[ i ][ j ] = fac[ j ][ i ];

}

}

d = detrm( num, r );

inv[ i ][ j ] = 0;

for ( i = 0;i < r;i++ )

{

for ( j = 0;j < r;j++ )

{

inv[ i ][ j ] = b[ i ][ j ] / d;

}

}

printf( " THE INVERSE OF THE MATRIX: " );

for ( i = 0;i < r;i++ )

{

for ( j = 0;j < r;j++ )

{

printf( " %f", inv[ i ][ j ] );

}

printf( " " );

}

}

/*************FUNCTION TO FIND TRANSPOSE AND INVERSE OF A MATRIX**************************/
void trans( float num[ 4 ][ 6 ], float fac[ 4 ][ 6 ], float r )
{
int i, j;
float b[ 4 ][ 6 ], inv[ 4 ][ 6 ], d;
for ( i = 0;i < r;i++ )
{
for ( j = 0;j < r;j++ )
{
b[ i ][ j ] = fac[ j ][ i ];
}
}
d = detrm( num, r );
inv[ i ][ j ] = 0;
for ( i = 0;i < r;i++ )
{
for ( j = 0;j < r;j++ )
{
inv[ i ][ j ] = b[ i ][ j ] / d;
}
}
printf( " THE INVERSE OF THE MATRIX: " );
for ( i = 0;i < r;i++ )
{
for ( j = 0;j < r;j++ )
{
printf( " %f", inv[ i ][ j ] );
}
printf( " " );
}
}

Ask to user for number in the 2 array

#include <iostream>

using namespace std;

#define m 3

#define n 3

int main()

{

     int i, j;

     int x[m][n]={{1,2,5}, {2,2,43},{2,4,1}};

   

     cout<<"---------table------------- ";

     // the outer for loop, reading the row by row...

     for(i=0; i<m; i++)

            // the inner loop, for every row, read every column by column...

            for(j=0; j<n; j++)

                  cout<<"["<<i<<"]"<<"["<<j<<"]"<<"="<<x[i][j]<<" ";

     return 0;

}

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