Date Format Conversion : Create a simple data file like the example shown below

Question

Date Format Conversion: Create a simple data file like the example shown below containing the 4 dates below plus 10 or more additional dates. The file should include 1 date per line and each date should have the form:    Month DayOfTheMonth, Year.   All dates should be in this century. No error checking for invalid dates is necessary.

February 19, 2017

July 4, 2017

November 4, 2018

September 30, 2019

         .

         .

         Write a program that will read the dates in the input date file and create an output data file with the form MonthNumber-DayOfTheMonth-Last2DigitsOfTheYear with no extra spaces. Example:

2-19-17

7-4-17

11-4-18

9-30-19

         .

         .only use these libraries

#include <iostream>
#include <string>
#include <cctype>
#include <cmath>
#include <iomanip>
#include <sstream>
#include <fstream>
#include <vector>
#include <algorithm>
#include <numeric>

Explanation / Answer

Here is the code for you. If you have any further queries, just get back to me:

#include <iostream>
#include <fstream>
using namespace std;
int main()
{
string month;
int monthNumber;
int day;
int year;
char temp;
string fileName;
ifstream ipFile;
cout<<"Enter the file name: ";
cin>>fileName;
ipFile.open(fileName);
while(!ipFile.eof())
{
ipFile>>month;
ipFile>>day;
ipFile>>temp;
ipFile>>year;
if(month == "January")
monthNumber = 1;
else if(month == "February")
monthNumber = 2;
else if(month == "March")
monthNumber = 3;
else if(month == "April")
monthNumber = 4;
else if(month == "May")
monthNumber = 5;
else if(month == "June")
monthNumber = 6;
else if(month == "July")
monthNumber = 7;
else if(month == "August")
monthNumber = 8;
else if(month == "September")
monthNumber = 9;
else if(month == "October")
monthNumber = 10;
else if(month == "November")
monthNumber = 11;
else
monthNumber = 12;   
cout<<monthNumber<<"-"<<day<<"-"<<year%2000<<endl;
}
}

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