Solve the following problem on paper and bring your sheet of paper to your secti

Question

Solve the following problem on paper and bring your sheet of paper to your section on Thursday: Array Simulation. You are to simulate the execution of a method that manipulates an array of integers. Consider the following method: public for if list Below are a list of specific lists of integers. You are to indicate what values would be stored in the list after methods mystery executes if the given integer list is passed as a parameter to mystery. {2, 4} {1, 2, 3} {2, 2, 2, 2, 2} {1, 2, 2, 2, 2} {2, 4, 6, 8} Show your work by writing the array's initial contents and then crossing out elements and writing new values as they change.

Explanation / Answer

Solution list1 = {2, 4} Condition i =1 Checking for loop, for (int i = 1; i list[1-1]) if (list[1]>list[0]) if (2 > 1) à satisfies Executing the step, list[i+1] = list[i-1] + list[i+1]; list[1+1] = list[1-1] + list[1+1]; list[2] = list[0] + list[2]; list[2] = 1 + 3; list[2] = 4; Since for loop increments the i value Check with Condition i =2 Checking for loop, for (int i = 2; i list[1-1]) if (list[1]>list[0]) if (2 > 2) à not satisfies since the condition of if loop fails, the loop terminates Since all list values are similar if loop fails all the time new list2 = {2, 2, 2, 2, 2} list4 = {1, 2, 2, 2, 2} Condition i =1 Checking for loop, for (int i = 1; i list[i-1]) if (list[1]>list[1-1]) if (list[1]>list[0]) if (2 > 1) à satisfies Executing the step, list[i+1] = list[i-1] + list[i+1]; list[1+1] = list[1-1] + list[1+1]; list[2] = list[0] + list[2]; list[2] = 1 + 2; list[2] = 3; list4 = {1, 2, 3, 2, 2} Since for loop increments the i value Check with Condition i =2 Checking for loop, for (int i = 2; i list[i-1]) if (list[2]>list[2-1]) if (list[2]>list[1]) if (3 > 2) à satisfies Executing the step, list[i+1] = list[i-1] + list[i+1]; list[2+1] = list[2-1] + list[2+1]; list[3] = list[1] + list[3]; list[3] = 2 + 2; list[3] = 4; list4 = {1, 2, 3, 4, 2} Since for loop increments the i value Check with Condition i =3 Checking for loop, for (int i = 3; i list[i-1]) if (list[3]>list[3-1]) if (list[3]>list[2]) if (4 > 3) à satisfies Executing the step, list[i+1] = list[i-1] + list[i+1]; list[3+1] = list[3-1] + list[3+1]; list[4] = list[2] + list[4]; list[4] = 3 + 2; list[4] = 5; list4 = {1, 2, 3, 4, 5} Since for loop increments the i value Check with Condition i =4 Checking for loop, for (int i = 4; i list[1-1]) if (list[1]>list[0]) if (4 > 2) à satisfies Executing the step, list[i+1] = list[i-1] + list[i+1]; list[1+1] = list[1-1] + list[1+1]; list[2] = list[0] + list[2]; list[2] = 2 + 6; list[2] = 8; list5 = {2, 4, 8, 8} Since for loop increments the i value Check with Condition i = 2 Checking for loop, for (int i = 2; i list[i-1]) if (list[2]>list[2-1]) if (list[2]>list[0]) if (8 > 2) à satisfies Executing the step, list[i+1] = list[i-1] + list[i+1]; list[2+1] = list[2-1] + list[2+1]; list[3] = list[1] + list[3]; list[3] = 4 + 8; list[3] = 12; list5 = {2, 4, 6, 12} Since for loop increments the i value Check with Condition i = 3 Checking for loop, for (int i = 3; i

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