I am having trouble developing this program. I know it needs to use a nested if

Question

I am having trouble developing this program. I know it needs to use a nested if statement in a for loop. It will rely upon a parralell array. Can somebody please help? The requirements are below.

Create a program that will accept any number of grades for an exam. The grades will be input as 4 for an A, 3 for a B, 2 for a C, 1 for a D, and 0 for an F. If the user enters an invalid number, reject it and ask again. After all grades have been entered, allow the user to enter -1 to exit. Output the number of grades in each category by using a loop and a parallel array (for the grade names). Do not use the switch command in C++, you are practicing the nested if statement.

Thanks

Explanation / Answer

This Program can be solved without array as follows:

#include<iostream>
using namespace std;

bool findElement(int nums[], int element, int numssize)
{
    for(int x = 0; x < numssize; x++)
    {
        if (nums[x] = element)
        {
            return 1;
        }

    }

return 0;
}

int main() {
    int a=0,b=0,c=0,d=0,f=0;
    bool acc=true;
    while (acc==true)
    {
        cout <<"Enter a grade ";
        string grade;
        cin >> grade;
        if (grade=="4")
        {
            a=a+1;
        }
        else if (grade=="3")
        {
            b=b+1;
        }
        else if (grade=="2")
        {
            c=c+1;
        }
        else if (grade=="1")
        {
            d=d+1;
        }
        else if (grade=="0")
        {
            f=f+1;
        }
        else if (grade=="-1")
        {
            acc=false;
        }
        else
        {
            cout << "Invalid grade, please re-enter ";
        }

    }

    cout << "Count of Grade A: " << a;
    cout << " Count of Grade B: " << b;
    cout << " Count of Grade C: " << c;
    cout << " Count of Grade D: " << d;
    cout << " Count of Grade F: " << f;

}

In the above code replace string with int to accept only int, string is safe since it wont throw an error if user enters a non number.

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