1. (Basic Pointers and Pointer Arithmetic) Write a C program that will do the fo

Question

1. (Basic Pointers and Pointer Arithmetic) Write a C program that will do the following:

    a. Create two integer variables x and y, and an integer array z[5]

    b. Set the variable x equal to 5, and the variable y equal to 10

    c. Save the following values in the array: 1, 2, 4, 8, 16

    d. Print to screen the address of each of the variables, x, y, and the start of the array z

    e. Create a pointer named testPtr and point it to the variable x

    f. Print to screen the value stored in variable x using only your pointer testPtr

    g. Add six to the value stored in x using only your pointer testPtr

    h. Print to screen the value stored in variable x using only your pointer testPtr

    i. Test to see if the value stored in variable x is larger than y, using only the variable y and the testPtr. If it is, print to screen "x > y", otherwise print "y < x"

    j. Now, change testPtr to Point to the first entry of the array z

    k. Using only testPtr, use a counter and for loop to print all the value in the array (do not use the array).

Explanation / Answer

#include <stdio.h>
#include <stdlib.h>
using namespace std;

int main()
{
   //a.
   int x,y,z[5];
  
   //b.
   x = 5;
   y = 10;
  
   //c.
   z[0] = 1;
   z[1] = 2;
   z[2] = 4;
   z[3] = 8;
   z[4] = 16;
  
   //d.
   printf("Address of x = %d, y= %d, z = %d",&x,&y,&z[0]);
  
   //e.
   int *testPtr = &x;
  
   //f.
   printf("Value of x is : %d",*testPtr);
  
   //g.
   *testPtr = *testPtr+6;
  
   //h.
   printf("Value of x is : %d",*testPtr);
  
   //i.
   if(y>(*testPtr))
       printf("y>x");
   else
       printf("y<x");
      
   //j.
   testPtr = &z[0];
  
   //k.
   for(int i=0;i<5;i++)
       printf("Value at %d is %d ",i+1,*(testPtr+i));
  
    return 0;

}

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