C++ programming Students from CSCE 206 attended a test that had two versions of

Question

C++ programming

Students from CSCE 206 attended a test that had two versions of the exam, Version_A, and Version_B.

15 students received version A, and their scores are 52, 86, 95, 23, 78, 89, 52, 81, 97, 45, 35, 84, 75, 94, 26 8 students received version B, and we don’t know their scores. Hence, ask the user to enter scores for 8 students [ Validation: All scores must be > 10 ]

Create two arrays Version_A, and Version_B, and populate them with the scores accordingly. The program must use Arrays and loops.

Compute: Version A mean score

Version B mean score

Mean score, when both version A and B scores are combined

Least score, when both version A and B scores are combined

Highest score, when both version A and B scores are combined

Explanation / Answer

#include <iostream>

using namespace std;

int main()
{

   int version_a[15] = {52, 86, 95, 23, 78, 89, 52, 81, 97, 45, 35, 84, 75, 94, 26};
   int version_b[8];
  
   for(int i=0;i<8;i++)
   {
       cout << "Input score number " << i+1 << " for version-b : ";
       while(true)
       {
      
           cin >> version_b[i];
      
           if(version_b[i]<=10)
           {
               cout << "Score should be greater than 10. Please input again: ";
               continue;
           }
           else
               break;
       }
   }
  
   int suma = 0,sumb = 0;
   int min = version_a[0],max = version_a[0];
  
   for(int i=0;i<15;i++)
   {
       suma = suma + version_a[i];
      
       if(version_a[i]>max)
           max = version_a[i];
          
       if(version_a[i]<min)
           min = version_a[i];
   }
  
  
   for(int i=0;i<8;i++)
   {
       sumb = sumb + version_b[i];
      
       if(version_b[i]>max)
           max = version_b[i];
          
       if(version_b[i]<min)
           min = version_b[i];  
   }
  
   cout << "Version-A mean score : " << suma*1.0/15 << endl;
   cout << "Version-B mean score : " << sumb*1.0/8 << endl;
   cout << "Version-A Version-B combined mean score : " << (suma+sumb)*1.0/23 << endl;
   cout << "Version-A Version-B combined least score : " << min << endl;
   cout << "Version-A Version-B combined highest score : " << max << endl;
  
    return 0;

}

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