Use function GetUserInfo to get a user\'s information. If user enters 20 and Hol

Question

Use function GetUserInfo to get a user's information. If user enters 20 and Holly, sample program output is:

Holly is 20 years old.

#include iostream

#include string

using namespace std;

void GetUserInfo(int& userAge, string& userName) {

cout << "Enter your age: " << endl;
cin >> userAge;
cout << "Enter your name: " << endl;
cin >> userName;
return;
}

int main() {
int userAge = 0;
string userName = "";

/* Your solution goes here */

cout << userName << " is " << userAge << " years old." << endl;

return 0;
}

Explanation / Answer

#include<iostream>

#include<string>

using namespace std;

void GetUserInfo(int &userAge, string &userName)

{

cout << "Enter your age: " << endl;

cin >> userAge;

cout << "Enter your name: " << endl;

cin >> userName;

return;

}

int main() {

int userAge = 0;

string userName = "";

/* Your solution goes here */

GetUserInfo(userAge, userName);

cout << userName << " is " << userAge << " years old." << endl;

return 0;

}

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