How do you do the following function void PrintHexValueAtIndex(char * c, int ind

Question

How do you do the following function

void PrintHexValueAtIndex(char * c, int index)

{

}

in C++ ?

Print the hexadecimal value of the character at the requested index

Example below.

Sample Usage

Sample Output

ReadString(pc, SIZE);

int length = 0;

GetStringLength(pc, &length);

for(int i = 0; i < length; ++i)

{

std::cout << "HEX=";

PrintHexValueAtIndex(pc, i);

std::cout << std::endl;

}

Enter a string less than 80 characters.

abcdABCD

HEX=61

HEX=62

HEX=63

HEX=64

HEX=41

HEX=42

HEX=43

HEX=44

Sample Usage

Sample Output

ReadString(pc, SIZE);

int length = 0;

GetStringLength(pc, &length);

for(int i = 0; i < length; ++i)

{

std::cout << "HEX=";

PrintHexValueAtIndex(pc, i);

std::cout << std::endl;

}

Enter a string less than 80 characters.

abcdABCD

HEX=61

HEX=62

HEX=63

HEX=64

HEX=41

HEX=42

HEX=43

HEX=44

Explanation / Answer

#include // Needed to use IO functions using namespace std; int main() { int sumOdd = 0; // For accumulating odd numbers, init to 0 int sumEven = 0; // For accumulating even numbers, init to 0 int upperbound; // Sum from 1 to this upperbound int absDiff; // The absolute difference between the two sums // Prompt user for an upperbound cout > upperbound; // Use a while-loop to repeatedly add 1, 2, 3,..., to the upperbound int number = 1; while (number sumEven) { absDiff = sumOdd - sumEven; } else { absDiff = sumEven - sumOdd; } // Print the results cout

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