Question 7 3 pt public atatie void main (Stringt arga) i object1 list new Object

Question

Question 7 3 pt public atatie void main (Stringt arga) i object1 list new Object (3]: list t0 null; list [1 new Object list (2-"a string value" llat necti try f insert code here catch (IndexoutofBoundsException e) f System.out.print ("IndexoutofBoundsException,) catch (Null PointerException e) ( System.out.print("Nu11PointerException, ") catch (Exception e) f System.out.print ("Exception, finally System.out.print ("Einally, ") System.out.print (end") Indicate what is printed if the code is inserted in the try block of the method above. Jgnore any wordwrap in the responses boolean aBoolean-list[0]null; end

Explanation / Answer

Answer: finally, end

Explanation: The given code is

boolean aBoolean = list[0] == null;

The above code works as follows, it checks if list[0] == null, and then assign the result of the check to aBoolean. If we observe the we can see that list[0] is assigned null so list[0] == null returns true and hence aBoolean is assigned true.

The code executes perfectly fine and there is will be no case for an exception to raise. As there are no exception, the control moves to the finally block after finishing the code execution in the try block. It prints finally, from the finally block and then prints end. Hence the ouput of the given code will be finally, end.

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