public class MathToolbox { /** This method should return true if and only if the

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 public class MathToolbox {      /** This method should return true if and only if the input i is a positive       * prime number. A prime is a number which is only divisible by 1 and            * itself (however the numbers 0 and 1 are not considered primes).           */     public static boolean isPrime(int i) {             // DELETE THE LINE BELOW ONCE YOU IMPLEMENT THE CALL!         throw new RuntimeException("not implemented!");         }                  /** This method will return the total number of primes in the range between       * lower and upper, including lower and upper themselves.       *       * Hint: it's possible to use isPrime(int i) as part of the computation.       */         public static int numPrimes(int lower, int upper) {             // DELETE THE LINE BELOW ONCE YOU IMPLEMENT THE CALL!         throw new RuntimeException("not implemented!");         }                  /** Find the factorial of n, which is given by n! = 1*2*...*(n-1)*n. The            * factorial of zero is a special case which is equal to 1.           */         public static int factorial(int n) {             // DELETE THE LINE BELOW ONCE YOU IMPLEMENT THE CALL!         throw new RuntimeException("not implemented!");         }                  /** Sums the series 1^p+2^p+...+(n-1)^p+n^p.           */         public static double sumPower(int n, double p) {             // DELETE THE LINE BELOW ONCE YOU IMPLEMENT THE CALL!         throw new RuntimeException("not implemented!");         }      /** Sums up the elements in list, but only including the elements x in list            * for which low <= x <= high.       */                   public static int boundedSum(int[] list, int low, int high) {             // DELETE THE LINE BELOW ONCE YOU IMPLEMENT THE CALL!         throw new RuntimeException("not implemented!");         }      /** Assume that list and filterList are lists of the same length. Then if the       * elements in list are l0, l1, ..., l(n-2), l(n-1) and the elements in filterList            * are f0, f1, ..., f(n-2), f(n-1), then this method will return            * l0*f0+l1*f1+...+l(n-2)*f(n-2)+l(n-1)*f(n-1).                   */         public static double filteredSum(double[] list, double[] filterList) {             // DELETE THE LINE BELOW ONCE YOU IMPLEMENT THE CALL!         throw new RuntimeException("not implemented!");         }                  /** Computes the geometric mean of the numbers in list. If the n numbers in       * list are l0, l1, ..., l(n-2), l(n-1), then the geometric mean is defined       * as the nth root of the product l0*l1*...*l(n-2)*l(n-1).           * You may assume that the list is not empty and the numbers are all positive.       *       * Hint: you may use the built-in Math.pow().           */         public static double geometricMean(double[] list) {             // DELETE THE LINE BELOW ONCE YOU IMPLEMENT THE CALL!         throw new RuntimeException("not implemented!");         }                  /** Considering the set of differences between consecutive elements in list,            * this method returns the largest. Consecutive difference is defined as            * the latter element minus the earlier element, i.e. list 1 - list 0. If there            * are not enough elements in the list to compute any differences, then the             * method should return zero by default.           */         public static int largestConsecutiveDiff(int[] list) {             // DELETE THE LINE BELOW ONCE YOU IMPLEMENT THE CALL!         throw new RuntimeException("not implemented!");         }                  /** A duplicate element is an element which appears more than once in the list.            * This method returns the largest element in list which has any duplicates            * whatsoever. If none of the elements have duplicates (every element in the            * list is unique) then this method should return Integer.MIN_VALUE.           */         public static int largestElementWithDups(int[] list) {             // DELETE THE LINE BELOW ONCE YOU IMPLEMENT THE CALL!         throw new RuntimeException("not implemented!");         }                  /** Assume that list and freqs are lists of the same size. For each element in list,            * this method should count the number of times that elements occurs in the list,            * and store the value in the same spot in freqs.       *       * For example, if list[3] == 4, and the number 4 appears a total of 7 times in list,       * then the value 7 should be stored in freqs[3]. The same goes for all elements in            * freqs           */         public static void findElementFreqs(int[] list, int[] freqs) {             // DELETE THE LINE BELOW ONCE YOU IMPLEMENT THE CALL!         throw new RuntimeException("not implemented!");                  }          }

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