The fine people at Dub Enterprises produce an ultrasound transducer that capture

Question

The fine people at Dub Enterprises produce an ultrasound transducer that captures a 4 x 2 pixel greyscale image. Below, in the thick-bordered box, is a map of the image. The map allows us to associate each pixel of the image with an index number from 0 to 7, so that we can uniquely identify each pixel in the image. Also shown outside the box is the coordinate system for the images: X increasing right, Y increasing down. For instance, pixel (2.1) has index 6. The bit depth of the image is 4. That means each pixel's level of grey is stored using 4 bits. 1) If our bit depth is 4, how many bytes of storage do we need to store one pixel? 2) If the entire 4 bits stores color/grey information, how many levels of grey are available for each pixel? 3) If we are mapping binary to decimal one-to-one (that is, binary 0 decimal 0, binary 1- decimal 1, and so on), what is the largest number we can store in our four bits per pixel? Give the number in binary and decimal. How many bits of information are in our entire 4 x 2 image? How many bytes? How many megabytes (MB)? (Hint: There are 1024 kB in one MB.) 4)

Explanation / Answer

1. ) As we will need a maximum of four bit we will need an only half byte to store one pixel.

2. ) As 4 bit can store 16 different value, So 16 levels of grey are available for each pixel.

3. ) We can store 1111 maximum in case of binary which is 15 in case of the decimal.

4.) There are 8 * 4 bits of information in entire image which is 32 bit which is 4 byte . Which is 4e-6 MB i.e 4 * 10^-6 .

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