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1. Suppose that Bob sends 90,000 bits to Alice over a 2.25 Kbps link (note, 1 Kb

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Question

1. Suppose that Bob sends 90,000 bits to Alice over a 2.25 Kbps link (note, 1 Kbps 103 bps) that uses circuit switching. Suppose that circuit switching on the link is implemented using TDM, that a frame is 1 sec, and that a frame consists of 6 slots. Bob is assigned one slot in every frame. How many minutes does it take Bob to transmit all bits to Alice? 2. Suppose that Router A and Router B are connected via a 10 Kbps link, and that the two routers are 50 meters apart. Suppose that Router A is transmitting a packet, and that there are 6 additional packets in the queue of the router, when a new packet arrives at Router A. Suppose that 700 bits of the currently-being-transmitted packet has been transmitted by Router A. Also, assume the following a. Every packet consists of 1000 bits b. Propagation speed of a bit over the link connecting the two routers is 2 x 104 meters/sec. c. Processing delay of a (whole) packet at a router takes 10 milliseconds (i.e., 0.01 seconds) What is the total delay of the new packet, i.e., how long does it take the new packet to arrive at Router B from the time it arrived at Router A? In your solution, clearly identify all four delay components the new packet experiences

Explanation / Answer

1. Since nothing is provided about the circuit being used it is being assumed that there is no delay because of the circuit.

For every minute Bob can transmit for only 10 sec.

Bob requires a total time of 90000/2250 = 40 sec.

For every 10 sec Bob has to wait 1 minute.

Bob has to wait for a total of 4 minutes to transmit the whole message.