write a program in C that converts decimals to binary. 1. No “magic numbers”, i.
ID: 3744948 • Letter: W
Question
write a program in C that converts decimals to binary.
1. No “magic numbers”, i.e., do not have literal values other than -1, 0, 1 or 2 in your code (use the #define pre-processor directive).
2. It’s ne to have leading 0’s in your output but don’t have “too many”.
3. Group the bits of the output into bytes and all on one line (see the Sample output section).
4. Do not use any user-dened functions, arrays, strings, conditional branches or loops for this program JUST KEEP THINGS SIMPLE!
sample output:
davids@hello$ ./a.out
Enter a valid unsigned short: 139
11010001 00000000
davids@hello$
Explanation / Answer
Given below is the code for the question.
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#include <stdio.h>
#define NUM_BITS 16
#define BYTE 8
int main()
{
unsigned short decimal;
int i;
unsigned short n, remainder;
printf("Enter a valid unsigned short: ");
scanf("%hu", &decimal);
n = decimal;
for(i = 1;i <= NUM_BITS; i++)
{
remainder = n % 2;
printf("%hu", remainder);
n = n / 2;
if(i % BYTE == 0) //need to print a space after a byte
printf(" ");
}
printf(" ");
}
output
======
Enter a valid unsigned short: 139
11010001 00000000
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