2. Consider the following strings variable definitions. char sl\"love\"; char s2

Question

2. Consider the following strings variable definitions. char sl"love"; char s2"to program!"; char s3[] = "I am, therefore char s4 [80]; "; strcpy (s4, "CSE 5A!"); What gets printed? printf( "%c", s4 [2] ); printf( "%d", strlen( s4 ) printf( "%d", sizeof( s1 ) ); ); Fill in the blanks to complete the following tasks: /*Change 'A' in string s4 to 'a' without explicitly assigning the value 'a'*/ ; /* Cannot have 'a here! For example, you CANNOT do something like: blahblahblah-'a' /Change the ',' in string s3 to '!'*/ /*The resulting output is "I love CSE 5A!" in a single printf ) statement. */ printf( "%

Explanation / Answer

Print statement values are :

1. printf("%c", s4[2]);           E
2. printf("%d", strlen(s4));       7
3. printf("%c", sizeof(s1));       5

4. s4[5] = tolower(s4[5]);

5. s3[4] = '!';

6. printf("%c %s %s", s3[0], s1, s4);

Please find complete code in bold -

#include <string.h>
#include <iostream>
#include <cstring>
#include <ctype.h>

using namespace std;

int main()
{
    char s1[] = "love";
   char s2[] = "to program!";
   char s3[] = "I am, therefore...";
   char s4[80];

    strcpy(s4, "CSE 5A!");
  
   printf("%c", s4[2]);
   printf(" ");
   printf("%d", strlen(s4));
   printf(" ");
   printf("%d", sizeof(s1));
   printf(" ");
  
   s4[5] = tolower(s4[5]);
    s3[4] = '!';
  
    printf("%c %s %s", s3[0], s1, s4);
    return 0;
}

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