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10.7 Does the following code compile? If it does not, how can it be fixed? If it

ID: 3738601 • Letter: 1

Question

10.7 Does the following code compile? If it does not, how can it be fixed? If it does, what is it's output? Does it throw an exception? If so, how can it be fixed? class Exa extends RuntimeException f) class Exb extends RuntimeException t public class Flow public static void main (String [] args) I try [ try f System.out.println ("stepu1"); if (true) throw new Exa catch (Exa a) f System.out.println ("stepu2" if (true) throw new ExbO h finally f System.out.println ("stepu3") System.out.println("stepu4" catch(Exception ex) t t h step 1 step 2 step 3

Explanation / Answer

Yes. the following given code compile succesfully. There are no complie time errors in the given program.

The output is already given:

step 1

step 2

step 3

Explanation to the question "why it did not print step 4 in the output"

Becasue, in the given code, it is throwing an exception throw new Exb(); and this excption is thrown inside the inner try block and at the same time this excption is not handled by the inner try.

But note that, any unhandled excptin in the inner try will be handled by the outer catch. Hence after throwing expetion with throw new Exb(), that exceptin will be handled by the outer catch after statements in the finally block are executed. So step 4 will never be excetued and it is a dead code.

For reference:

class Exa extends RuntimeException {

}

class Exb extends RuntimeException {

}

public class Flow {

public static void main(String[] args) {

try {

try {

System.out.println("step 1");

if (true)

throw new Exa();

} catch (Exa a) {

System.out.println("step 2");

if (true) throw new Exb();

} finally {

System.out.println("step 3");

}

System.out.println("step 4");

} catch (Exception ex) {

System.out.println("step 5");

}

}

}

Output:

step 1
step 2
step 3
step 5

Proof: excpetion occured in the inner try block due to throw new Exb() which is unhandled inside the inner, but handled by the outer try-catch block and it prints the step 5 as in the output

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