A host X, with IP address 200.100.70.10 and a MAC address of “A” has a packet to

Question

A host X, with IP address 200.100.70.10 and a MAC address of “A” has a packet to send another host Y with IP address 200.100.70.100, but its MAC address is unknown. Fill in the blank to create an ARP request, and an appropriate Ethernet frame:

IP asks ARP to create an ARP broadcast message, filling in sender physical address    A   , sender IP address                   , target MAC address             .          

The resulting ARP packet is passed onto the data link layer, where it gets encapsulated in a link frame using, physical address                   as a source address, and physical               address as the destination address.

Explanation / Answer

Solution:-

ARP Request : sender physical address = MAC address of host X = A

sender ip address = IP address of host X = 200.100.70.10

destination ip address = IP address of host Y = 200.100.70.100

destination physical address = MAC address for the host Y = FF:FF:FF:FF:FF:FF

This ARP request is broadcasted by the host X to get the actual MAC address related to the corresponding ip address of 200.100.70.100.

Frame in data-link layer:

physical address as a source address = sender MAC address = "A"

physical address as a destination address = receiver MAC address = MAC address obtained by ARP response packet for the host Y.

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