Java Write a program that models a list of possibly overlapping rectangular twod

Question

Java

Write a program that models a list of possibly overlapping rectangular twodimensional windows, like the windows for the programs open on your computer.
Use an ArrayList to store the windows. The order of the windows in the list implies the order in which they would display on the screen (sometimes called the “zorder”), from 0 on the bottom to size() – 1 on the top.

You must use StdDraw, not Swing, to complete this project.

Here is how the program should run:

https://www.youtube.com/watch?v=ChCI6M8q1OY&feature=youtu.be

Explanation / Answer

public class Rectangles
{

private final double x;
private final double y;

private final double width;
private final double height;

public Rectangles(double x0, double y0, double w, double h)
{
x = x0;
y = y0;
width = w;
height = h;

}
public double area()
{
return width * height;
}
public double perimeter()
{
return 2*width + 2*height;
}

public boolean intersects(Rectangles b)
{
boolean leftof = ((b.x + (0.5*b.width))<(x-(0.5*width)));
boolean rightof = ((b.x-(0.5*b.width))>(x+(0.5*width)));
boolean above = ((b.y-(0.5*b.height))>(y+(0.5*height)));
boolean below = ((b.y+(0.5*b.height))<(y-(0.5*height)));
if (leftof==true || rightof==true || above==true || below==true)
return false;
else return true;

}

public void show()
{
double j = Math.max((x+(0.5*height)), (y+(0.5*height)));
StdDraw.setYscale((0),j+1);
StdDraw.setXscale((0),j+1);
StdDraw.setPenColor();
StdDraw.rectangle(x,y,.5*width,.5*height);
}

public static void main(String[] args)
{
Rectangles a = new Rectangles(Double.parseDouble(args[0]),
Double.parseDouble(args[1]),
Double.parseDouble(args[2]),
Double.parseDouble(args[3]));
Rectangles b = new Rectangles(2,2,2,2);
System.out.println(a.area());
System.out.println(a.perimeter());
System.out.println(a.intersects(b));
a.show();

}

}

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