For NetBeans JAVA: The bookstore sells items to students, faculty/staff and the
ID: 3726403 • Letter: F
Question
For NetBeans JAVA:
The bookstore sells items to students, faculty/staff and the public. There are M visitors and N cashiers in the bookstore at any given time. Visitors typically wander around shopping for items then line up to cash out. Cashiers service visitors on a first come first served basis. Write a program to synchronize the visitors and cahiers using semaphores and/or monitors. Follow the guidelines and instructions below:
- Prompt the user for the values of M and N. Assume an upper bound on M is 50 and N is 10.
- Assume the number of items each person carries to the cashier is between 1 and 6 and that they shop for between 50 to 75 time units per item.
- Assume it takes between 10 and 20 time units for a cashier to checkout an item.
- Show: the number of people shopping, the number of people waiting in the cashier line and the number of people being served.
Have all of these:
Proper use of threads/semaphores
Master process functions correctly
Visitors function correctly
Cahiers function correctly
Proper graphical display of numbers identified in 4 above
Proper shutdown … all threads exit properly
Comments in code
Explanation / Answer
As per your requirement the below one is solution please follow it
program:
class Cashier{
public static time = Math.random()*((20-10)+1)+10;
}
class Visitor extends Cashier{
public static item = Math.random()*((6-1)+1)+1;
public static time = Math.random()*((75-50)+1)+50;
private Semaphore semaphore;
public Visitor(Semaphore semaphore) {
this.semaphore = semaphore;
}
private void criticalCode()
{try {
sleep(item*Cashier.time);
} catch (InterruptedException e) {
}
}
public void run()
{
int count=0;
try {
semaphore.acquire();
criticalCode();
semaphore.release();
count++;
} catch (InterruptedException e) {
System.out.println("Exception " + e.toString());
}
System.out.println("The number of people being served:" + count);
}
}
public class BookStore{
public static void main(String args[]){
Scanner sc = new Scanner(System.in);
int m = sc.nextInt();
int n = sc.nextInt();
Semaphore semaphore = new Semaphore(n, true);
Visitor p[] = new Visitor[m];
for (int i = 0; i < n; i++)
{
int count=0;
p[i] = new Visitor(semaphore);
count ++;
p[i].start();
}
System.out.println("The number of people waiting:" + count);
}
}
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