Help explain the answer to this question Assume alist is a list of integer eleme

Question

Help explain the answer to this question

Assume alist is a list of integer elements and stk is a stack of integers. A pair of loops first copies the elements from the list to the stack and then copies the elements from stack back to the list. Compare the order of the elements (select a or b) in the original list and the final list. Loop 1: while(alist.empty)) stk.push (alist.back)) alist.pop_back Loop 2: while(!stk.empty )) alist.push front (stk.top ()) stk.pop) The two copies produce the same ordering in the new list The two copies reverse the ordering in the new list 4 of 4

Explanation / Answer

In the Loop 1:

The right most element of aList is in the bottom of stk and the first element of aList is at the top of stk.

In Loop 2:

Here, the top most elements of the stack if pushed at the front of the list.

So, the bottom most element in stk will be the first element of aList.

So, the order of the list is now reversed.

Answer : (b)

Related Questions

Navigate

• Browse (All)
• Browse H
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.