!, 3, 4 is not correct. I have checked it. Question 4 1 pts 1. The best-fit plac

Question

!, 3, 4 is not correct. I have checked it.

Question 4 1 pts 1. The best-fit placement policy is slower on average than the first-fit placement policy. 2. The next-fit placement policy chooses the smallest free block into which the requested memory fits 3. For an implicit free list that is ordered by increasing block sizes, first-fit placement policy minimizes internal fragmentation. 4. For an explicit free list that is unordered by block size, best-fit placement policy minimizes internal fragmentation Which of the statements above are true? 1 and 2 1, 2 and 3 4 only 3 and 4 O 1,3 and 4

Explanation / Answer

Answer)

The best fit placement policy is slower in average than the first fit placement policy - True, this is because Best-fit memory allocation makes the best use of memory space but slower in making allocation.

The next fit placement policy chooses the smallest free block into which the requested memory fits - False, as the next fit placement policy begins as a first fit policy to find a free partition to allocate and next time it starts searching from where it left off

For an implicit free list that is ordered by increasing block sizes, first fit placement policy minimizes internal fragmentation - True, The first fit placement policy minimizes internal fragmentation when the list is ordered in increasing block sizes as the best matching blocks are placed in the slots.

For an explicit free list that is unordered by block size, best fit placement policy minimizes internal fragmentation - True, For an unordered list best fitment policy will reduce the internal fragmentation as there will be less space wasted because of optimal placement of block sizes.

So Answer will be 1,3,4

Related Questions

Navigate

• Browse (All)
• Browse #
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.