(15 pt.) A red and a blue die are thrown. Both dice are loaded (that is, not all
ID: 3721175 • Letter: #
Question
(15 pt.) A red and a blue die are thrown. Both dice are loaded (that is, not all sides are equally likely). Rolling a 2 with the red die is twice as likely as rolling each of the other five numbers and rolling a 4 with the blue die is twice as likely as rolling each of the other five numbers. a. b. c. (5 pt.) What is the probability of each outcome of the red die? (5 pt.) What is the probability of each outcome of the blue die? (5 pt.) What is the probability that the sum of the numbers on the two dice is 6?Explanation / Answer
Let probability of rolling other 5 numbers on red dice = x
The, probability of rolling 2 on red dice = 2x
so 5x + 2x = 1 => x = 1/7
Let probability of rolling other 5 numbers on blue dice = y
The, probability of rolling 4 on blue dice = 2y
so 5y + 2y = 1 => y = 1/7
a) Probability of each outcome on red die
1- 1/7
2- 2/7
3- 1/7
4- 1/7
5- 1/7
6- 1/7
b) Probability of each outcome on Blue die
1 - 1/7
2 - 1/7
3 - 1/7
4 - 2/7
5 - 1/7
6 - 1/7
c)
Sum of nos. as 6 for both die
Various possible combinnations (Red, Blue) with probabilities as below
(1,5) - (1/7(1/7)
(2,4) - (2/7)(2/7)
(3,3) - (1/7)(1/7)
(4,2) - (1/7)(1/7)
(5,1) - (1/7)(1/7)
Overall probability - 4. (1/7)^2 + (2/7)^2 = 0.163265
Related Questions
Navigate
Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.