ME-Q1) Given the following definition of the classes Animal, Lion, and Jumpable,

Question

ME-Q1) Given the following definition of the classes Animal, Lion, and Jumpable, select the correct combinations of assignments of a variable that don't result in compilation errors or runtime exceptions (select 2 options). interface Jumpable ( class Animal class Lion extends Animal implements Jumpable [h 539 WOW! eBook www.wowebook.org CHAPTER 8 Full mock exam a Jumpable var1 = new Jumpable(); ? b Animal var2 = new Animal () ; [ ] c Lion var3 new Animal ( ) ; d Jumpable var4 e Jumpable var5 f Jumpable var6 new Animal () ; new Lion() ; (Jumpable) (new Animal ( )) ;

Explanation / Answer

1. Jumpable var1 = new Jumpable();
error, interfaces cannot be instantiated.

2. Animal var2 = new Animal();
No error, proper code. Since, animal is a class and can be instantiated of that type only.

3. Lion var3 = new Animal();
Error, since a child class cannot refer to a parent class type.

4. Jumpable var4 = new Animal();
Error, since jumpable and animal are incompatible types.

5. Jumpable var5 = new Lion();
No error, since an interface can refer to an object that implements an interface, Lion being the case this time.

6. Jumpable var6 = (Jumpable) new Animal();

Answer:

Option 2

Option 5

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