URGENT PLEASE check if my code is right and correct it if it isnt #include <stdi

Question

URGENT PLEASE check if my code is right and correct it if it isnt

#include <stdio.h>

int sum(int *x,int *f)

{

int i, fSum, sum1=0, sum2=0, size=10;

for(i=0;i<size;i++)

{

if (i%2==0)

sum1 += (2*f[i])-(3*x[i]);

else

sum2 += (6*f[i+1])+x[i];

}

fSum=(.5*sum1)+(.6*sum2);

return fSum;

}

int main()

{

int size=10;

int x[10] = {2,1,5,-3,6,7,8,10,3,9};

int *xptr=x;

int f[10] = {2,5,7,3,5,-8,7,4,1,9};

int *fptr=f;

int i;

printf("Array x: ");

for(i=0;i<size;i++)

printf("%d ",x[i]);

printf(" ");

printf("Array f: ");

for(i=0;i<size;i++)

printf("%d ",f[i]);

printf(" ");

printf("Sum is: %d ",sum(x,f));

return 0;

}

This is the question

Define two arrays x={2,1,5,-3,6,7,8,10,3,9} and f={2,5,7,3,5,-8,7,4,1,9} each size 10 using call by reference(pointers) to pass the array to a function named sum.

In main define array, print out array, pass array to the function and print out the returned value on the screen. In funtion sum take arrays from main and sum the arrays using

Explanation / Answer

There is a small mistake

:sum2 += (6*f[i+1])+x[i];

This line should be

:sum2 += (6*f[i])+x[i];

You are already checking for even and odd, there is no need of writing i+1

The new output is:

Sum is:47

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