Write a (POSIX) program that searches for a specified file, and if found, prints

Question

Write a (POSIX) program that searches for a specified file, and if found, prints out the relative path of the file from the current working directory and its time stamp. Your program should take one command line argument, the filename to find. If your executable file is “searchFile” and you run this program from the root directory (“/”) and search for a file named “test.txt”. Your output might be something like the following:

$./searchFile test.txt

Searching for test.txt …

Found test.txt in /home/user/CIS324/

Last Edited: Jun 7 10:30

Explanation / Answer

void SearchDirectory(string directory, string target_File_Name){ DIR *dirp = opendir(directory.c_str()); if (!dirp) { perror(("opendir " + directory).c_str()); return; } struct dirent *dptr; while(dptr = readdir(dirp)){ string file_Name = dptr->d_name; string file_Path = directory + "/" + file_Name; struct stat statStruct; stat(file_Path.c_str(), &statStruct); if( S_ISDIR(statStruct.st_mode) ){ if ( file_Name.compare(".") == 0 || file_Name.compare("..") == 0 ){ continue; } SearchDirectory(file_Path, target_File_Name); } else if( S_ISREG(statStruct.st_mode)){ if( file_Name.compare(target_File_Name) == 0){ cout

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