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Write a program that displays the binary representation of an integer as a \'1\'

ID: 3712851 • Letter: W

Question

 Write a program that displays the binary      representation of an integer as a '1' is     shifted through all 32 bits of an integer     storage location.     Also print the:       - Decimal value of the integer       - The decimal value of each byte         in the integer       - The binary value of each byte         in the integer     Use the program from the examples, binary.c,     as a starting point         Ex:    --                  Integer: 1                  Binary: 00000000000000000000000000000001                   Bytes:        1        0        0        0                  Binary: 00000001 00000000 00000000 00000000                                  Integer: 2                  Binary: 00000000000000000000000000000010                   Bytes:        2        0        0        0                  Binary: 00000010 00000000 00000000 00000000                                  Integer: 4                  Binary: 00000000000000000000000000000100                   Bytes:        4        0        0        0                  Binary: 00000100 00000000 00000000 00000000                                               .                           .                           .                    Integer: 2147483648                  Binary: 10000000000000000000000000000000                   Bytes:        0        0        0      128                  Binary: 00000000 00000000 00000000 10000000    

Explanation / Answer

#include <iostream>

using namespace std;

int main()
{
    int dec;
    cout << "Enter the decimal to be converted: ";
    cin >> dec;

    int bin32[] = {0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0};
    for (int pos = 31; pos >= 0; --pos)
    {
        if (dec % 2)
            bin32[pos] = 1;
        dec /= 2;
    }

    cout << "The binary of the given number is: " << endl;
     for (int p = 0; p <= 31; p++)
    {
      
        cout<<bin32[p];
    }
    cout << " The decimal value in each 8 bit is: " << endl;
    int k=31 ,l=23,base=1,dec_value = 0;
  
    for(int i=0;i<4;i++)
    {
        for(int j=k; j>l; --j)
        {
            dec_value =dec_value+ bin32[j]*base;
            base = base*2;
        }
        base=0;
        cout<<dec_value<<" ";
        dec_value=0;
        base=1;
        k=k-8;
        l=l-8;
    }
}

Thanks;

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