Q2 Given the constant and variable declarations #define E 2.78 #define MAX 100 d

Question

Q2 Given the constant and variable declarations #define E 2.78 #define MAX 100 double x, y; int a, b, i; indicate which of the following statements are valid and where valid, give the value stored into the target variable. Assume that a is 4, b is 3, and y is -2.0 (a) 1 a%b; (c ) a % b * b; (e) x-E*y (g) X-E y (i) x=a%(a / b); (k) x (double) a / b; (b) -(MAX -90)/a; (d) x=a/y; (f) a*E; (h)x b/a; (j) x-b%(b / a); (I) x = (double) (a/ b); Redo the above question with new values of 3 for a, 7 for b, and 3.0 for y

Explanation / Answer

Answer 2:

a) Valid statement

i = 1

simple modulus operator

b) Valid statement

i = 2

c) Valid statement

i = 3

d) Valid statement

x = -2.00000

e) Valid statement

x = -5.560000

f) Valid statement

i = 11

g) Valid statement

x = -1.390000

h) Valid statement

x = 0.000000

i) Valid statement

x = 0.000000

j) Statement is valid, but no value will be assigned to the x because b/a will give 0 and then 3%0 will give something like....

k) Valid statement

x = 1.333333

because type casting is performed on a so a first will cast to double then division will be performed.

l) Valid statement

x = 1.000000

because type casting is performed on (a/b), first division will be performed then will be casted in double.

Note: As above we can easily find out the values for a =3, b= 7, and y = 3.0.

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