v) Consider the following ASM code. Assume this has been assembled and run on SC

Question

v) Consider the following ASM code. Assume this has been assembled and run on SCOMP. ORG &H000; Begin program at x000 Start: LOAD A SUB B JNEG Neg LOAD C JUMP Next Neg: LOADD Next: ADD A STORE E Done: JUMP Done A: DW &H0001; B: DW &H0002; C: DW &H0003; D: DW &HFFFE; E: DW&H0005; DD: EQU &HFFFF; What is stored in location "E" at the end of program (i.e., after it starts looping forever at "Done")? &H000; b) &HFFFF; c) &H0004; d)&HFFFE; e) None of the above

Explanation / Answer

Answer is as follows :

Load A // Load the value of i.e. &H0001 to accumulator i.e. equal to 1 in hexadecimal

SUB B // Subtract value of B i.e. H0002 from Accumulator , So 0002 - 0001 = -1 i.e. negtive.

JNEG NEG // Check if value of Accumulator is negative. Yes it is negative than jump to label NEXT.

So at Neg.

Load D // load the value of D to Accumulator i.e. $HFFFFE i.e. FFFE in hexadecimal.

ADD A// Add the contents of A i.e. 0001 to Accumulator So , FFFE + 0001 = FFFF

STORE E // Store the value at variable E, so E contains &HFFFF in hexadecimal.

So from above the correct option is B i.e. &HFFFF.

// lines are explanation of corresponding instruction and working of program.

if there is any query please ask in comments..

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