Date: Address Contents 0x10010004 0x213FED1E 0x1001000 Ox1 122334F Register Cont

Q: Date: Address Contents 0x10010004 0x213FED1E 0x1001000 Ox1 122334F Register Cont

1. lb $21 , -3($22) //load byte at address ($22-3) into $21 Content at $22 -3 i.e 0x10010009 is 9D Content of $21 becomes 0x0000009D 2. lw $21 , -8($22) //Load contents of address ($22 - 8) into register $21 ($22 - 8) = 0x1001000C - 0x10010004 = 0x10010004 content at address 0x10010004 is stored in $21 i.e. content of $21 = 0x213FED1E Register Contents $21 $22 0x1001000C

ID: 3705005 • Letter: D

Question

Date: Address Contents 0x10010004 0x213FED1E 0x1001000 Ox1 122334F Register Contents 0x10010000 0x98272ACA $21 | 822 | 0x1001000C | | 0x10010008 | 0x219DEFAD Consider the following information above Please give the full 32-bit value inside the register in hexadecimal.: lb $21, -3(822) 1. (5 Points) What is the contents of register 21 after executing the following instruction. 2. (5 Points) What is the contents of register 21 after executing the following instruction. Please give the full 32-bit value inside the register in hexadecimal. lw $21, -8(822)

Explanation / Answer

lb $21 , -3($22) //load byte at address ($22-3) into $21

Content at $22 -3 i.e 0x10010009 is 9D

Content of $21 becomes 0x0000009D

lw $21 , -8($22) //Load contents of address ($22 - 8) into register $21

($22 - 8) = 0x1001000C - 0x10010004

= 0x10010004

content at address 0x10010004 is stored in $21 i.e. content of $21 = 0x213FED1E

Navigate

Date: A Analyse this foasiliferous rock from New York (Fig. A.31A 1. What index

Date: April 11, 2018 Score: I. An amount 8000 is invested in an account at an ef

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.

Date: Address Contents 0x10010004 0x213FED1E 0x1001000 Ox1 122334F Register Cont

Question

Explanation / Answer

Related Questions

Navigate