Part II -Review for Final Exam . The purpose of writing these programs is to pra

Question

Part II -Review for Final Exam . The purpose of writing these programs is to practice indexing through a vector using loops. . For each of these problems, do not use the MATLAB commands: sort, sum, min, and max. . Use the following vector for all problems: V 17 9 -89 3-8-5 1 10 10 0 -7] Note: You should use the MATLAB command length(V) to allow you to determine the length of a generic vector. Use this value as the STOP value in your for loop. for k- START:1:STOP end Problem 1: Write a script file that will determine how many entries in a vector are larger than some specified value. The user should input the specified value. The outputs will be the following statement: "The number of entries larger than (display your specified value here) is: (display the number of entries here)". You should use Jprintf to display the statement with your values embedded. Paste below the script file and the fprintf outputs using the vector, V, and the specified value of 3 Problem 2: Write a script file that will find the sum of all the positive entries in V and the sum of all the negative entries in V. An fprintfstatement should be used to display the value for the sum of all the positive entries and the sum of all the negative entries. Reminder: don't use the built-in function, sum Paste below the script file and the fprintf outputs using the vector: V statement should be used to display the largest entry and the smallest entry Reminder: don't use the built-in functions max or min Paste below the script file and the fprintf outputs using the vector: D

Explanation / Answer

Problem 1:

V = [ 7 9 -8 9 3 -8 -5 1 10 10 0 -7 ];

prompt = 'Enter a number : ';

% get user input

n = input(prompt);

count = 0;

% traverse through V

for i = 1 : length(V)

   

   % if current element is greater than n

   if V(i) > n

      

      count = count + 1;

      

   end

   

end

fprintf(' No of elements greater than % d : %d ', n, count);

Sample Output

Enter a number : 4

No of elements greater than 4 : 5

Problem 2:

V = [ 7 9 -8 9 3 -8 -5 1 10 10 0 -7 ];

% store sum of positive numbers

pos_sum = 0;

% store sum of negative numbers

neg_sum = 0;

% traverse through V

for i = 1 : length(V)

   

   % if current element is positive

   if V(i) >= 0

      

       pos_sum = pos_sum + V(i);

     

   % if current element is negative

   else

      

       neg_sum = neg_sum + V(i);

      

   end

   

end

fprintf(' Sum of positive numbers : %d ', pos_sum);

fprintf('Sum of negative numbers : %d ', neg_sum);

Sample Output

Sum of positive numbers : 49
Sum of negative numbers : -28

Problem 3:

V = [ 7 9 -8 9 3 -8 -5 1 10 10 0 -7 ];

% store maximum element

max_val = V(1);

% store minimum element

min_val = V(1);

% traverse through V

for i = 2 : length(V)

   

   % if current element is greater than max_val

   if V(i) > max_val

      

       max_val = V(i);

      

   end

     

   % if current element is smaller than min_val

   if V(i) < min_val

      

       min_val = V(i);

      

   end

   

end

fprintf(' Minimum element : %d ', min_val);

fprintf('Maximum element : %d ', max_val);

Sample Output

Minimum element : -8
Maximum element : 10

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