Use the following routing Linux table for the questions below Default 10.0.0.0 1

Question

Use the following routing Linux table for the questions below Default 10.0.0.0 10.4.10.0 10.5.10.O 10.2.10.0 255.0.0.0 255.255.255.0 255.255.255.0 255.255.255.0 GatewaY 10.0.0.1 10.1.0.1 10.4.10.1 10.5.10.3 Interfacse eth2 etho etho ethi eth3 What will the next hop IP address be for packets to each of the following destination IP addresses be and what Ethernet interface will they be sent to? 1. 192.168.1.15 2. 10.15.5.45 3. 10.2.10.18 4. 10.4.12.13 5. 10.0.02 6. 207.82.12.23 What do the network address and net mask look like for the default entry in a routing table? 7. What do the network address and net mask look like for a route to a specific host in routing table? 8.

Explanation / Answer

As per Chegg policy, I am answering only first 4 subparts of first Question. Kindly upload the remaining questions again in order to know their solution.

1.) With netmask 255.255.255.0. network address of 192.168.1.15 evaluates to 192.168.1.0 which corresponds to default and its next IP address will be 10.0.0.1 and it will be sent to eth2.

2.) With netmask 255.0.0.0. network address of 10.15.5.45 evaluates to 10.0.0.0. So its next IP address will be 10.1.0.1 and it will be sent to eth0.

3.) With netmask 255.255.255.0. network address of 10.2.10.18 evaluates to 10.2.10.0. So its next IP address is not given and it will be sent to eth3.

4.) With netmask 255.0.0.0. network address of 10.4.12.13 evaluates to 10.0.0.0. So its next IP address will be 10.1.0.1 and it will be sent to eth0. For IP address 10.4.12.13 with subnet mask 255.255.255.0, network address will be 10.4.12.0 and we didn't have any gateway or interface for this network address.

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