v.o(15pts) Build the routing table for Router A n the following table. Router C

Question

v.o(15pts) Build the routing table for Router A n the following table. Router C is a border gateway router which gets the advertisement of 144.122.212.0/22 from another A.S. The AS of Router A uses OSPF for intra-AS routing. i sement. 144.122.212.0/22 Int Int AD Int AB E 144.122.216.0121 122. a) Complete the Logical Routing Table of Router A using the necessary algorithm in the table below. Indicate the routing protocol (s) that is used to construct each entry. Algorithm (Use as many rows as you need): Current set De D), p(D) Logical Routing Table: Interface (AB, AC or AD) Subnet 144.122.208.0/20 44.122.208.0/21 144.122.216.0/21 144.122.212.0/22 Rout tocols (OSPF, BGP)

Explanation / Answer

Building the Routing Table

Without a populated directing table that contains sections for remote systems, switches won't have the capacity to forward parcels to those remote systems. The steering table may incorporate particular system passages or essentially a solitary default course. The data in the steering table is utilized by the sending procedure to forward activity to the goal system or host. The steering table itself does not in reality forward activity.

Cisco switches utilize the regulatory separation, steering convention metric, and the prefix length to figure out which courses will really be put into the directing table, which enables the switch to assemble the directing table. The steering table is assembled utilizing the accompanying general advances:

In the event that the course passage does not as of now exist in the steering table, add it to the directing table

On the off chance that the course section is more particular than a current course, add it to the steering table. It ought to likewise be noticed that the less particular section is still additionally held in the steering table

In the event that the course passage is the same as a current one, however is gotten from a more favored course source, supplant the old section with the new passage

On the off chance that the course passage is the same as a current one, and is gotten from a similar convention:

Dispose of the new course if the metric is higher than the current course

Supplant the current course if the metric of the new course is lower

In the event that the metric for the two courses is the same, utilize the two courses for stack adjusting

When constructing the RIB, of course, the steering convention with the most reduced authoritative separation esteem will dependably win when the switch is figuring out which courses to put into the directing table. For instance, if a switch gets the 10.0.0.0/8 prefix by means of outer EIGRP, OSPF, and inward BGP, the OSPF course will be put into the directing table. In the event that that course is expelled or is never again gotten, the outside EIGRP course will be set into the steering table. Lastly, if both the OSPF and outside EIGRP courses are never again present, the interior BGP course is utilized.

When courses have been set into the directing table, as a matter of course the most particular or longest match prefix will dependably be favored over less particular courses. This is shown in the accompanying illustration which demonstrates a steering table that contains passages for the 80.0.0.0/8, 80.1.0.0/16, and the 80.1.1.0/24 prefixes. These three course prefixes are gotten by means of the EIGRP, OSPF, and RIP directing conventions, individually.

R1#show ip course

Codes: C – associated, S – static, R – RIP, M – portable, B – BGP

D – EIGRP, EX – EIGRP outside, O – OSPF, IA – OSPF bury territory

N1 – OSPF NSSA outside sort 1, N2 – OSPF NSSA outer compose 2

E1 – OSPF outer compose 1, E2 – OSPF outside sort 2

I – IS-IS, L1 – IS-IS level-1, L2 – IS-IS level-2, ia – IS-IS entomb zone

* – hopeful default, U – per-client static course, o – ODR

P – intermittent downloaded static routeGateway of final resort isn't set

R 80.1.1.0/24 [120/1] by means of 10.1.1.2, 00:00:04, Ethernet0/0.1

D 80.0.0.0/8 [90/281600] by means of 10.1.1.2, 00:02:02, Ethernet0/0.1

O E2 80.1.0.0/16 [110/20] by means of 10.1.1.2, 00:00:14, Ethernet0/0.1

Referencing the yield appeared over, the primary course is the 80.1.1.0/24 course. This course is found out by means of RIP and in this way has a default regulatory separation estimation of 120. The second course is the 80.0.0.0/8 course. This course is found out by means of inward EIGRP and along these lines has a default managerial separation estimation of 90. The third course is the 80.1.0.0/16 course. This course is found out by means of OSPF and is an outside OSPF course that has an authoritative separation of 110.

NOTE: Because the steering convention measurements are unique, they are a non-factor in deciding the best course to utilize when courses from numerous conventions are introduced into the directing table. The accompanying area will depict how Cisco IOS switches fabricate the directing table

In light of the substance of this steering table, if the switch got a bundle bound to 80.1.1.1, it would utilize the RIP course since this is the most particular section, despite the fact that both EIGRP and OSPF have better managerial separation esteems and are in this way more favored course sources. The show ip highway 80.1.1.1 order can be utilized to confirm this announcement:

R1#show ip highway 80.1.1.1

Directing passage for 80.1.1.0/24

Known by means of "tear", separate 120, metric 1

Redistributing by means of tear

Keep going refresh from 10.1.1.2 on Ethernet0/0.1, 00:00:15 prior

Steering Descriptor Blocks:

* 10.1.1.2, from 10.1.1.2, 00:00:15 prior, by means of Ethernet0/0.1

Course metric is 1, movement share tally is 1

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