Does the following execution satisfy linearizability? If not, remove one operati

Question

Does the following execution satisfy linearizability? If not, remove one operation so that the execution satisfies linearizability.

I understand that linearizability requires an execution to be valid and perserve per-node and real-time order, but am struggling to apply it to this execution. Particularly confused about what 1 = R(x) means. My intuition is that we must remove 1 = R(x) because 1 has already been overwritten with y, so you would be reading y instead of x at that point. Any help or guidance is appreciated!

Explanation / Answer

as per linearizability rule for register we need to read a register after every write of that register.

In this case we first we write x to 1 by process 1 and then we write 2 in it. so after this we need to read 2 from x only so Need to remove  1 = R(x) to make it linearizability . For else it is working fine as we write it before than read of it.

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