10. Write a method called removeInRange that accepts three parameters, an ArrayL

Question

10. Write a method called removeInRange that accepts three parameters, an ArrayList of strings, a beginning string, and an ending string, and removes from the list any strings that fall alphabetically between the start and end strings. For example, if the method is passed a list containing the elements ["to", "be", "or", "not", "to", "be", "that", "is", "the", "question"], "free" as the start String, and "rich" as the end String, the list’s elements should be changed to ["to", "be", "to", "be", "that", "the"]. The "or", "not", "is", and "question" should be removed because they occur alphabetically between "free" and "rich". You may assume that the start string alphabetically precedes the ending string.

Explanation / Answer

ArrayListTest.java

import java.util.ArrayList;

public class ArrayListTest {

   /**
   * @param args
   */
   public static void main(String[] args) {
       // TODO Auto-generated method stub
       ArrayList list= new ArrayList<String>();
       list.add("to");
       list.add("be");
       list.add("or");
       list.add("not");
       list.add("to");
       list.add("be");
       list.add("that");
       list.add("is");
       list.add("the");
       list.add("question");
       list = removeInRange(list, "free", "rich");
       System.out.println(list);
   }
   public static ArrayList removeInRange(ArrayList<String> list, String beginning , String ending){
       char beginChar = beginning.charAt(0);
       char endChar = ending.charAt(0);
       ArrayList<String> list1 = new ArrayList<String>();
       for(int i=0; i< list.size(); i++){
           String s = list.get(i);
           if(!(s.charAt(0) >= beginChar && s.charAt(0) <= endChar)){
               list1.add(s);
           }
       }
       return list1;
   }
  
}

Output:

[to, be, to, be, that, the]

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