What is the output of the following code? int f() { return 1; } int main() { cou
ID: 3692439 • Letter: W
Question
What is the output of the following code?
int f()
{
return 1;
}
int main()
{
cout << f() << endl;
return 0;
}
1
1 0
nothing
0
0 1
Does the function call in the following function cause syntax errors?
#include <iostream>
#include <math>
using namespace std;
int main()
{
pow(2.0, 4);
}
Yes
No
Analyze the following code.
#include <iostream>
using namespace std;
int m(int num)
{
return num;
}
void m(int num)
{
cout << num;
}
int main()
{
cout << m(2);
}
The program has a syntax error because the two functions m have the same signature.
The program runs and prints 2 twice.
The program runs and prints 2 once.
The program has a syntax error because the second m function is defined, but not invoked in the main function.
1
1 0
nothing
0
0 1
Does the function call in the following function cause syntax errors?
#include <iostream>
#include <math>
using namespace std;
int main()
{
pow(2.0, 4);
}
Yes
No
Analyze the following code.
#include <iostream>
using namespace std;
int m(int num)
{
return num;
}
void m(int num)
{
cout << num;
}
int main()
{
cout << m(2);
}
The program has a syntax error because the two functions m have the same signature.
The program runs and prints 2 twice.
The program runs and prints 2 once.
The program has a syntax error because the second m function is defined, but not invoked in the main function.
Explanation / Answer
The code outputs 1.
Yes, the code has syntax error. #include<math> should be #include<cmath>
The program has a syntax error because the two functions m have the same signature.
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