How to determine JK flipflop\'s values? The problem: When E is 0, circuit remain

Question

How to determine JK flipflop's values?

The problem: When E is 0, circuit remains in the same state;

When E = 1, F = 1, circuit goes like 00, 01, 10, 11;

When E = 1, F = 0, circuit goes like 00, 11, 10, 01.

The following table is the correct answer. I am perfectly clear with the E, F, A, B, A+, B+ columns. However, I am confused about how the Ja, Ka, Jb, Kb values are determined. Please help! Thank you

Ky-X 0 X 0 X 0 X 0 X 1 X 1 X 1 X 1 X 0 X 0 X 0 X 1 X 1 X 1 X 1 X log K,-X X 0 0 X X 0 0 X X 1 0 X X 0 1 i J, 0 0 X X 0 0 X X 1 0 X X 0 1 X X 0101010110101010 xe { 0 0 1 1 0 0 1 1 1 0 0 1 0 1 10 B-0 1 0 1 0 1 0 1 0 1 0 1 0 1 0 1 PS4-0 0 1 1 0 0 1 1 0 0 1 1 0 0 1 1 F-0 0 0 0 1 1 1 1 0 0 0 0 1 1 1 1 In E-0 0 0 0 0 0 0 0 1 1 1 1 1 1 1 1

Explanation / Answer

to get the value of JK, we need this table

By that table,

if A =0 and A+=0 than JA=0 KA=X

if A =0 and A+=1 than JA=1 KA=X

if A =1 and A+=0 than JA=X KA=1

if A =1 and A+=1 than JA=X KA=0

same procedure for B

P P' J K 0 0 0 X 0 1 1 X 1 0 X 1 1 1 X 0

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