/*To make telephone numbers easier to remember, some companies use letters to sh

Question

/*To make telephone numbers easier to remember, some companies use letters to show their telephone number.
For example, using letters, the telephone number 438-5626 can be shown as GET LOAN.
In some cases, to make a telephone number meaningful, companies might use more than seven letters.
For example, 225-5466 can be displayed as CALL HOME, which uses eight letters. Write a program that prompts the user to enter a telephone number expressed in
letters and outputs the corresponding telephone number in digits. If the user enters more than seven letters, then process only the first seven letters.
Also output the – (hyphen) after the third digit. Allow the user to use both uppercase and lowercase letters as well as spaces between words.
Moreover, your program should process as many telephone numbers as the user wants. (You can use While and switch statements, Use a function,
called converting_letter_number, for converting letter to number to get a full credit).

p.s (please include comments, and dont use an array)

heres a piece of my code that I tried on my own:

#include <iostream>
using namespace std;

//
void converting_letter_number(char phoneNumber);
int main()
{
   //Define Variables
   int counter;
   char phoneNumber;
   char

   //Prompt User
   cout << "Enter a phone number in letters ONLY." << endl;
   cin >> phoneNumber;
   converting_letter_number(phoneNumber);
   for (counter = 0; counter > 7; counter++)
   {
       cin >> phoneNumber;

       if (counter = 3)
           cout << "-";
       converting_letter_number(phoneNumber);

   }
   system("pause");
   return 0;
}

void converting_letter_number(char phoneNumber)
{
   if (phoneNumber >= 'A' && phoneNumber <= 'Z' || phoneNumber >= 'a' && phoneNumber <= 'z')
       switch (phoneNumber)
       {
       case 'A':
       case 'a':
       case 'B':
       case 'b':
       case 'C':
       case 'c':
           cout << 2;
           break;
       case 'D':
       case 'd':
       case 'E':
       case 'e':
       case 'F':
       case 'f':
           cout << 3;
           break;
       case 'G':
       case 'g':
       case 'H':
       case 'h':
       case 'I':
       case 'i':
           cout << 4;
           break;
       case 'J':
       case 'j':
       case 'K':
       case'k':
       case 'L':
       case 'l':
           cout << 5;
           break;
       case 'M':
       case 'm':
       case 'N':
       case 'n':
       case 'O':
       case 'o':
           cout << 6;
           break;
       case 'P':
       case 'p':
       case 'Q':
       case 'q':
       case 'R':
       case 'r':
       case 'S':
       case 's':
           cout << 7;
           break;
       case 'T':
       case 't':
       case 'U':
       case 'u':
       case 'V':
       case 'v':
           cout << 8;
           break;
       case 'W':
       case 'w':
       case 'X':
       case 'x':
       case 'Y':
       case 'y':
       case 'Z':
       case 'z':
           cout << 9;
           break;
       default:
           cout << "Wrong input" << endl;

       }
}

Explanation / Answer

#include <iostream>
using namespace std;

void converting_letter_number(char phoneNumber);
int main()
{
//Define Variables
int counter;
char phoneNumber;
//Prompt User
cout << "Enter a phone number in letters ONLY." << endl;
for (counter = 0; counter < 7; )
{
cin >> phoneNumber;
if((phoneNumber>='a' && phoneNumber<='z') || (phoneNumber>='A' && phoneNumber<='Z'))
counter++;
else
continue;
if (counter == 4)
cout << "-";
converting_letter_number(phoneNumber);
}
return 0;
}
void converting_letter_number(char phoneNumber)
{
if (phoneNumber >= 'A' && phoneNumber <= 'Z' || phoneNumber >= 'a' && phoneNumber <= 'z')
switch (phoneNumber)
{
case 'A':
cout << 2;
break;
case 'a':
cout << 2;
break;
case 'B':
cout << 2;
break;
case 'b':
cout << 2;
break;
case 'C':
cout << 2;
break;
case 'c':
cout << 2;
break;
case 'D':
cout << 3;
break;
case 'd':
cout << 3;
break;
case 'E':
cout << 3;
break;
case 'e':
cout << 3;
break;
case 'F':
cout << 3;
break;
case 'f':
cout << 3;
break;
case 'G':
cout << 4;
break;
case 'g':
cout << 4;
break;
case 'H':
cout << 4;
break;
case 'h':
cout << 4;
break;
case 'I':
cout << 4;
break;
case 'i':
cout << 4;
break;
case 'J':
cout << 5;
break;
case 'j':
cout << 5;
break;
case 'K':
cout << 5;
break;
case'k':
cout << 5;
break;
case 'L':
cout << 5;
break;
case 'l':
cout << 5;
break;
case 'M':
cout << 6;
break;
case 'm':
cout << 6;
break;
case 'N':
cout << 6;
break;
case 'n':
cout << 6;
break;
case 'O':
cout << 6;
break;
case 'o':
cout << 6;
break;
case 'P':
cout << 7;
break;
case 'p':
cout << 7;
break;
case 'Q':
cout << 7;
break;
case 'q':
cout << 7;
break;
case 'R':
cout << 7;
break;
case 'r':
cout << 7;
break;
case 'S':
cout << 7;
break;
case 's':
cout << 7;
break;
case 'T':
cout << 8;
break;
case 't':
cout << 8;
break;
case 'U':
cout << 8;
break;
case 'u':
cout << 8;
break;
case 'V':
cout << 8;
break;
case 'v':
cout << 8;
break;
case 'W':
cout << 9;
break;
case 'w':
cout << 9;
break;
case 'X':
cout << 9;
break;
case 'x':
cout << 9;
break;
case 'Y':
cout << 9;
break;
case 'y':
cout << 9;
break;
case 'Z':
cout << 9;
break;
case 'z':
cout << 9;
break;
default:
cout << "Wrong input" << endl;
}
}

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