Assume that the following code is correctly inserted into a program: int s = 0;

Question

Assume that the following code is correctly inserted into a program: int s = 0; for (i = 0; i < 5; i++) { s = 2 * s + i; cout << s << " "; } cout << endl; a. What is the final value of s? (i) 11 (ii) 4 (iii) 26 (iv) none of these b. If a semicolon is inserted after the right parenthesis in the for loop statement, what is the final value of s? (i) 0 (ii) 1 (iii) 2 (iv) 5 (v) none of these c. If the 5 is replaced with a 0 in the for loop control expression, what is the final value of s? (i) 0 (ii) 1 (iii) 2 (iv) none of these

Explanation / Answer

a)(iii)26

final value of s is 26

the s value for each iteration are as follows 0

1

4

11

26

b) (iv)5

if we put selmicolon right side of the for the loop will make i value as 5;

theblock of code will not be looped.

s=2*s+i; //s=0,i=5

s=2*0+5=5

c) (i) 0

if we replace 5 with 0 the condition in loop is not satisfied so the loop wil not execute the block of code so the s vlaue will be the initially declare value s=0

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