Subnetting Exam Name: Joseph Tundidor Date: 04/26/2016 Use the following for que
ID: 3685513 • Letter: S
Question
Subnetting Exam
Name: Joseph Tundidor Date: 04/26/2016
Use the following for questions 1-6:
Class C Network ID of 192.20.17.0
Create 15 subnets
How many bits must be borrowed from the host address bits? One would need to borrow 4 bits, because the 1st bit would only create 2 subnets, the 2nd bit could create 4, the 3rd could create 8, and the 4th would create enough for 16, which is one more than needed but any memory left over can be used at a later time for further expansion.
What is/are the subnet mask(s) for the subnets, written in decimal?
What is the CIDR notation for the first subnet’s network ID? For the second subnets network ID?
How many host addresses are possible in each subnet?
What is the range of host addresses for the first subnet? For the last subnet?
What is the broadcast address for each subnet?
What is the last valid host on the subnetwork 172.31.185.0/24?
What is the broadcast address of the network 192.168.188.240 255.255.255.240?
How many subnets and hosts per subnet can you get from the network 192.168.42.0/28?
What is the first valid host on the subnetwork that the node 172.18.215.39/24 belongs to?
Explanation / Answer
1....
The last valid host on the subnetwork 172.31.185.0/24 is 172.31.185.38.
Remember the incremental value of 16 . So 24+ 16 = 40 being the next subnet.
I choose to find the valid host address the next subnet minus 2 and result = 38, in this case is uyour last valid host.
Alsdo you can count the host bits you have avalilable in this case 4 bits = 16 host minus 2 and you got 14 valid host. the you add 14 to 24and you got 38, being your first valid host. 172.31.185.0 -- and last 172.31.185.38.
2....
The broadcast address of the network 192.168.188.240 255.255.255.240 is 192.168.188.255.
3.....
The subnets and hosts per subnet can you get from the network 192.168.42.0/28 are : 16 subnets and 32 hosts
4...
The first valid host on the subnetwork that the node 172.18.215.39/24 belongs to 172.18.215.1
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