Write a program that creates an array of integers from 1 to 10 then : Include in

Question

Write a program that creates an array of integers from 1 to 10 then : Include in your program the following functions: A function that accepts the integer array and the array size as a arguments. The function should create a copy of the array, except the values will be reversed in the copy. The function should return a pointer to the new array. A function that accepts the integer array, and the array size as an argument. The function should create a new array that is twice the size of the original array. It should copy the original array information in and then initialize the unused elements to 0. It should return a pointer to the new array. A function that accepts the integer array and the array size as a arguments. It should print the array's data with spaces between the numbers Any other function you need. In main, call the reverse function, print then the doubling function and print.

Explanation / Answer

#include<iostream>
using namespace std;

int* reverse(int A[],const int n);
int* doubleIt(int A[],const int n);
void print(int A[],int n);

int main()
{
   const int size=10;
   int A[]={1,2,3,4,5,6,7,8,9,10};
   int *B = reverse(A,size);
   int *C = doubleIt(A,size);
    cout<<" Initial Array ";
   print(A,size);
   cout<<" After reverse function ";
   print(B,size);
    cout<<" After doubling function ";  
   print(C,2*size);
          
  
}

int* reverse(int A[],const int n)
{
   int *B=new int(n);
   int i=0;
   while(i<n)
   {
   B[i]=A[n-i-1];
   i++;
   }
   return B;
}

int* doubleIt(int A[],const int n)
{
   int *B=new int(n*2);
   int i=0;
   while(i<n*2)
   {
    if(i<n)
     B[i]=A[i];
    else
     B[i]=0;
    i++;
   }
   return B;
}

void print(int A[],int n)
{
int i =0;
   while(i<n)
   {
    cout<<A[i]<<" ";
    i++;
   }
}

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