In a factory, various metal pieces are forged and then plunged into a cool liqui
ID: 3681893 • Letter: I
Question
In a factory, various metal pieces are forged and then plunged into a cool liquid to quickly cool the metal. The types of metals produced, as well as their specific heat capacity, are listed in the table below.
Material Specific Heat [J/(g °C)]
Aluminum 0.897
Cadmium 0.231
Iron 0.450
Tungsten 0.134
The metal pieces vary in mass, and are produced at a temperature of 300 degrees Celsius. The ideal process lowers the temperature of the material to 50 degrees Celsius. The liquid used to cool the metal is glycerol. The properties of glycerol are listed below.
Material Property Value [Units]
Specific heat 2.4 J/(g °C)
Specific gravity 1.261
Initial temperature 25 °C
There are data sets from four different data collection sessions. In the first data collection session, a lab technician collected seven different measurements and recorded mass in grams of aluminum rods. The second data set contains cadmium rods; the third data set contains iron rods, and the fourth data set contains tungsten rods.
Mass of Object [g]
Aluminum Cadmium Iron Tungsten
2,000 3,000 2,500 4,800
2,500 4,000 3,500 6,400
3,000 6,500 4,500 10,400
4,000 8,000 5,000 12,800
5,500 10,000 5,500 16,000
7,500 11,000 7,500 17,600
8,000 15,000 9,000 24,000
Write a code in MATLAB that can calculate the thermal energy in joules that must be
removed for each rod to cool it from 300 to 50 degrees Celsius for each mass and (2) to
determine the volume of fluid needed in gallons to properly cool the rod for each mass. The
result from the second function should be a matrix with the first column being the mass of
the rod, and the second column the volume of fluid needed.
Our instructor does not want us to use functions for this question in MATLAB.
Somebody posted this question earlier but only got a troll answer.
Explanation / Answer
%Variables
%SH - matrix containing specific heat of the materials
%M - matrix containing the masses of the rods
%TE- thermal energy released by the rods [J]
%V- volume of glycerol needed to cool the rods [gal]
%Alum- matrix containing masses & amount of glycerol needed for aluminum
%rods
%Cadm- matrix containing masses & amount of glycerol needed for cadmium
%rods
%Iron- matrix containing masses & amount of glycerol needed for iron rods
%Tung- matrix containing masses & amount of glycerol needed for tungsten
clear
clc
%Set input matrices
SH=[0.897; 0.231; 0.450; 0.134];
M=[2000 3000 2500 4800; 2500 4000 3500 6400; 3000 6500 4500 10400; 4000 8000 5000 12800; 5500 10000 5500 16000; 7500 11000 7500 17600; 8000 15000 9000 24000];
%Calculate volume required to cool aluminum
TE_1=ThermalEnergy(M(:,1),SH(1));
V_1=FluidVolume(TE_1);
Alum=[M(:,1) V_1]
%Calculate volume required to cool cadmium
TE_2=ThermalEnergy(M(:,2),SH(2));
V_2=FluidVolume(TE_2);
Cadm=[M(:,2) V_2]
%Calculate volume required to cool iron
TE_3=ThermalEnergy(M(:,3),SH(3));
V_3=FluidVolume(TE_3);
Iron=[M(:,3) V_3]
%Calculate volume required to cool tungsten
TE_4=ThermalEnergy(M(:,4),SH(4));
V_4=FluidVolume(TE_4);
Tung=[M(:,4) V_4]
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