This program will be ran through a Python 3 IDE. The function avgavg() takes as

Question

This program will be ran through a Python 3 IDE.

The function avgavg() takes as input a list whose items are lists of three numbers. Each three-number list represents the three grades a particular student received for a course. For example, here is an input list for a class of four students:

[[95, 92, 86], [66, 75, 54], [89, 72, 100], [34, 0, 0]]

The function avgavg() should print, on the screen, two lines. The first line will contain a list containing every student's average grade. The second line will contain just one number: the average class grade, defined as the average of all student average grades.

Here is an example of how the function should work:

>>> avgavg([[95, 92, 86], [66, 75, 54], [89, 72, 100], [34, 0, 0]])

[91.0, 65.0, 87.0, 11.333333333333334]

63.5833333333

Explanation / Answer

For better readable code see here : http://pastebin.com/KsN2cJSa

def avgavg(lst):

studentAvg = []

for row in lst:

studentTotal=0

for item in row:

studentTotal=studentTotal+item #summing marks of a student

studentTotal=studentTotal/3 #Find student average

studentAvg.append(studentTotal) #add this avg to list of averages

print(studentAvg)

avgTotal=0

for item in studentAvg:

avgTotal=avgTotal+item #now add each avg to get overall average.

avgTotal=avgTotal/len(studentAvg) #divide by number of student

print (avgTotal) #dispaly overall average

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