How many memory addresses are needed for a 32-bit word? How big is the address s
ID: 3679064 • Letter: H
Question
How many memory addresses are needed for a 32-bit word?
How big is the address space of a SPARC process?
Where in the process address space are the executable instructions loaded?
Where in the process address space is the call stack?
What does it mean for a memory access to be aligned?
What section of the assembly code file contains static memory allocations?
What is a null-terminated ASCII string?
What is the largest data size that can be loaded or stored with one instruction?
How many instructions are necessary to load or store a 15-byte value?
What is the notation for the memory address used with the load and store mnemonics?
Why are there more load instructions than store instructions?
If a 32-bit word is stored to memory address 100, what is the address of the most significant byte?
What single instruction will round %l0 down to the nearest multiple of 8?
How do you expand the stack frame to make room for local variables?
Given a pointer to an array and an index, give a mathematical expression for the address of the element at that index
Explanation / Answer
1. Using n-bits we are going to need 2^n memory locations. so, to store a32 bit word we are going to use 2^32 memory addresses. that means 2^32 = 4 GB
2. The data segment of assembly containes static memory locations.
3. A mnemonic is a device that is used to help the memory. To store and load we use LDA and STA are used for storing and loading instructions instead of hexadecimal opcodes.
4. We use more load instructions than store instructions because to store a particular value into a memory location we can do this by using the store instruction. but during the programming we need the stored values in variables. in order to do this we use load instruction to load the variables.
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