Write a C++ program using a while loop to calculate the value of ?/2 accurate to

Question

Write a C++ program using a while loop to calculate the value of ?/2 accurate to 6 digits after the decimal point using the following series:

Can someone please help me with the set up for this problem? I'm not sure where to being here. Any help is much appreciated!

B) Write a C++ program using a while loon to calculate the value of /2 accurate to 6 digits after the decimal point using the following series: 2 3 3-5 3-5.7 Display the following and turn in printouts of the program and the results The number of terms needed to find /2 .The value of T/2 using acos-1)/2 using 10 digits after the decimal point. . The value of T/2 found with the series using 10 digits after the decimal point (the first 6 digits after the decimal point should match the value above).

Explanation / Answer

#include <iostream>

#include <iomanip>

int main()

{

int num=1,den=3,c;

double sum;

sum= 1+1/3;

//setting precision to 10

std::cout << std::fixed << std::setprecision(10) << sum;

c=2;//setting count=2 why because we have count for sum value 1,1/3 terms

double d=(acos(-1)/2);

//setting exact precision 10 i.e value after point is 10 digits

std::cout << std::fixed << std::setprecision(10) << d;

while(d==sum)

{

for(i=2;i<=c;i++)

{

num=num*(num+1);

den=den*(den+2);

}//for

sum=sum+(num/den);

c++;

}//while

cout << "The number of terms needed to pi/2 is "<<c;

}//main

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