Hi, I need help with this C++ programming problem. All you need to do is fill yo

Question

Hi, I need help with this C++ programming problem. All you need to do is fill your codes in the line that says Your solution goes here. Be sure to test your codes with different outputs. Here is the template for this problem (please use it):

Write a loop that sets newScores to oldScores shifted once left, with element 0 copied to the end. Ex: If oldScores = {10, 20, 30, 40}, then newScores = {20, 30, 40, 10}.

Note: These activities may test code with different test values. This activity will perform two tests, the first with a 4-element array (newScores = {10, 20, 30, 40}), the second with a 1-element array (newScores = {199}). See How to Use zyBooks.

Also note: If the submitted code tries to access an invalid array element, such as newScores[9] for a 4-element array, the test may generate strange results. Or the test may crash and report "Program end never reached", in which case the system doesn't print the test case that caused the reported message.

Template:

#include <iostream>
using namespace std;

int main() {
   const int SCORES_SIZE = 4;
   int oldScores[SCORES_SIZE];
   int newScores[SCORES_SIZE];
   int i = 0;

   oldScores[0] = 10;
   oldScores[1] = 20;
   oldScores[2] = 30;
   oldScores[3] = 40;

   /* Your solution goes here */

   for (i = 0; i < SCORES_SIZE; ++i) {
      cout << newScores[i] << " ";
   }
   cout << endl;

   return 0;
}

Thanks.

Explanation / Answer

#include <iostream>
#include <vector>
using namespace std;
int main()
{
const int SCORES_SIZE = 4;
vector<int> oldScores(SCORES_SIZE);
vector<int> newScores(SCORES_SIZE);
int i = 0;
oldScores.at(0) = 10;
oldScores.at(1) = 20;
oldScores.at(2) = 30;
oldScores.at(3) = 40;
for (i = 0; i < SCORES_SIZE; ++i)
{
newScores = oldScores;
newScores.push_back(0);
}
for (i = 0; i < SCORES_SIZE; ++i)
{
cout << newScores.at(i) << " ";
}
cout << endl;
return 0;
}

OR

for(int i=0; i<SCORES_SIZE; i++)
{
newScores[i] = oldScores[(i+1)%SCORES_SIZE];
}

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